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General

Easy

Question

# A friction clayton is in the form of the frustum of a cone, the diameters of the ends being 8cm, and 10cm and length 8cm Then its volume is

- 506.75 cm
^{3}
- 605.57 cm
^{3}
- 506.65 cm
^{3}
- 408.75 cm
^{3}

^{3}^{3}^{3}^{3}## The correct answer is: 506.75 cm^{3}

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