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Maths-

General

Easy

Question

ABCD is a Parallelogram DL $perpendicular to the power of r end exponent$ AB and DM $perpendicular to the power of r end exponent$ BC If AB = 18 cm, BC=12 cm and DM = 9 cm then find DL .

6cm
7cm
5cm
8cm

hint Hint:

Compare the corresponding bases and heights using the formula of the area of a parallelogram to get the answer.

The correct answer is: 6cm

$G i v e n comma D L perpendicular to the power of r A B D M perpendicular to the power of r B C A B equals 18 c m B C equals 12 c m D M equals c m T o space f i n d comma D L W e space k n o w space t h a t comma A r e a space o f space a space p a r a l l e log r a m equals b a s e cross times h e i g h t A r e a space equals space A B cross times D L equals B C cross times D M therefore 18 cross times D L equals 12 cross times 9 D L equals fraction numerator 12 cross times 9 over denominator 18 end fraction therefore D L equals 6 c m$

Related Questions to study

ABCD is a Parallelogram, DL $perpendicular to the power of r end exponent$ AB If AB = 20 cm, AD = 13 cm and area of the Parallelogram is 100 cm², find AL.

ABCD is a Parallelogram, DL $perpendicular to the power of r end exponent$ AB If AB = 20 cm, AD = 13 cm and area of the Parallelogram is 100 cm², find AL.

The base of a Parallelogram is twice its height If the area of the Parallelogram is 512 cm², then find the height

Therefore, height of the parallelogram is 16cm.

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Therefore, height of the parallelogram is 16cm.

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Therefore, the area of square is $3969 space c m squared$ .

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Therefore, the area of the rectangle is 60 cm².

Find the Area of a Rectangle whose length is 10 cm and breadth 6 cm

Therefore, the area of the rectangle is 60 cm².

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