Maths-
General
Easy
Question
Equation of a circle with centre (4, 3) touching the circle 
is
The correct answer is:
Let the circle touching the circle x2 + y2 = 1, be x2 + y2 – 8x – 6y + k = 0,
The equation of the common tangent is S1 – S2 = 0
i.e. 8x + 6y–1–k = 0
This is a tangent to the circle x2+y2 = 1.
Hence ± 1 = 
Þ k+1 = ± 10 Þ k = –11 or 9
Therefore the circles are x2+y2–8x–6y+9 = 0 and x2+y2–8x–6y–11 = 0
Hence (d) are the correct answers.
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