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Maths-

General

Easy

Question

Find the perimeter of the following figure.

10cm
20cm
15m
15cm

hint Hint:

Calculate the length of all the sides of the given figure.

The correct answer is: 15cm

$P e r i m e t e r space o f space t h e space f o l l o w i n g space f i g u r e equals space A B plus B C plus C D plus D E plus E F plus F G plus G A equals 4 plus 0.5 plus 2.5 plus 2.5 plus 0.5 plus 4 plus 1 equals 15 c m$

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5.6 m ....... cm

Therefore, 5.6m is equal to 560cm.

5.6 m ....... cm

Therefore, 5.6m is equal to 560cm.

In $triangle A B C comma angle B equals 45 to the power of ring operator end exponent comma angle C equals 55 to the power of ring operator end exponent$ and bisector of $angle$ A meets BC at a point D, then $angle$ ADB and $angle$ ADC are

In $triangle A B C comma angle B equals 45 to the power of ring operator end exponent comma angle C equals 55 to the power of ring operator end exponent$ and bisector of $angle$ A meets BC at a point D, then $angle$ ADB and $angle$ ADC are

The sides EF, FD and DE of a triangle DEF are produced in order forming three exterior angles DFP, EDQ and FER respectively Then $angle D F P plus angle E D Q plus angle F E R$ is

The sides EF, FD and DE of a triangle DEF are produced in order forming three exterior angles DFP, EDQ and FER respectively Then $angle D F P plus angle E D Q plus angle F E R$ is

parallel

In the given figure the side QR of $triangle P Q R$ has been produced to S If $angle P colon angle Q colon angle R equals 3 colon 2 colon 1$ and $text RT end text perpendicular text PR end text$ then ÐTRS is

In the given figure the side QR of $triangle P Q R$ has been produced to S If $angle P colon angle Q colon angle R equals 3 colon 2 colon 1$ and $text RT end text perpendicular text PR end text$ then ÐTRS is

The displacement vector is represented by

The displacement vector is represented by

physics-General

True vector are shown in figure find the correct options

True vector are shown in figure find the correct options

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The vector are shown as following figure find the correct statement

The vector are shown as following figure find the correct statement

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Which of the following is equal to $sec to the power of 2 end exponent invisible function application theta plus text cose end text text c end text to the power of 2 end exponent theta$

Which of the following is equal to $sec to the power of 2 end exponent invisible function application theta plus text cose end text text c end text to the power of 2 end exponent theta$

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Which of the following is equal to $open parentheses 1 minus sin to the power of 2 end exponent invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta$

Which of the following is equal to $open parentheses 1 minus sin to the power of 2 end exponent invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta$

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Which of the following is equal to cosec²

Which of the following is equal to cosec²

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Value of sin20° + cos20°

Value of sin20° + cos20°

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Value of $tan invisible function application theta equals fraction numerator 2 over denominator square root of 5 end fraction comma$ find the value of sin²0^O +cos²0^O

Value of $tan invisible function application theta equals fraction numerator 2 over denominator square root of 5 end fraction comma$ find the value of sin²0^O +cos²0^O

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The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

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The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

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In the given figure, if $P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end text$ and $text end text angle Q R T equals 65 to the power of ring operator end exponent comma$ then the values of x and y respectively are

In the given figure, if $P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end text$ and $text end text angle Q R T equals 65 to the power of ring operator end exponent comma$ then the values of x and y respectively are

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