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Question

If A= open square brackets table row 1 3 row 3 4 end table close square brackets and A2T – kA – 5I2 = O, then the value of k is-

  1. 3    
  2. 5    
  3. 7    
  4. –7    

The correct answer is: 5


    We are given with matrix A and also the equation of k and asked to find the value of k
    A squared minus 5 I subscript 2 space equals space end subscript open square brackets table row 1 3 row 3 4 end table close square brackets space open square brackets table row 1 3 row 3 4 end table close square brackets space minus 5 space open square brackets table row 1 0 row 0 1 end table close square brackets
equals open square brackets table row 5 15 row 15 20 end table close square brackets space equals space 5 space open square brackets table row 1 3 row 3 4 end table close square brackets
H e n c e space t h e space v a l u e space o f space k space equals 5

    Hence we find that the value of k is 5

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