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If A open parentheses table row 1 3 4 row 3 cell negative 1 end cell 5 row cell negative 2 end cell 4 cell negative 3 end cell end table close parentheses equals open parentheses table row 3 cell negative 1 end cell 5 row 1 3 4 row cell plus 4 end cell cell negative 8 end cell 6 end table close parentheses then A equals negative times

  1. open parentheses table row 1 0 0 row 0 1 0 row 0 0 cell negative 2 end cell end table close parentheses    
  2. open parentheses table row 0 1 0 row 1 0 0 row 0 0 1 end table close parentheses    
  3. open parentheses table row 1 0 0 row 1 0 0 row 0 0 cell negative 2 end cell end table close parentheses    
  4. open parentheses table row 0 1 0 row 1 0 0 row 0 0 cell negative 2 end cell end table close parentheses    

The correct answer is: open parentheses table row 0 1 0 row 1 0 0 row 0 0 cell negative 2 end cell end table close parentheses


    By observation its obvious that R subscript 1 end subscript & R subscript 2 end subscript are interchanged & R subscript 3 end subscript of R.H S minus 2 times R subscript 3 end subscript of L.H S
    i.e R subscript 1 end subscript rightwards arrow R subscript 2 end subscript comma R subscript 3 end subscript rightwards arrow negative 2 R subscript 3 end subscript equals A equals open parentheses table row 0 1 0 row 1 0 0 row 0 0 cell negative 2 end cell end table close parentheses

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