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Question

If A –2B = open square brackets table row 1 5 row 3 7 end table close square brackets and 2A – 3B = open square brackets table row cell negative 2 end cell 5 row 0 7 end table close square brackets, then matrix B is equal to–

  1. open square brackets table row cell negative 4 end cell cell negative 5 end cell row cell negative 6 end cell cell negative 7 end cell end table close square brackets
  2. open square brackets table row 0 6 row cell negative 3 end cell 7 end table close square brackets
  3. open square brackets table row 2 cell negative 1 end cell row 3 2 end table close square brackets
  4. open square brackets table row 6 cell negative 1 end cell row 0 1 end table close square brackets

The correct answer is: open square brackets table row cell negative 4 end cell cell negative 5 end cell row cell negative 6 end cell cell negative 7 end cell end table close square brackets


    We have

    B = (2A –3B) –2 (A –2B) = 2open square brackets table row cell negative 4 end cell cell negative 5 end cell row cell negative 6 end cell cell negative 7 end cell end table close square brackets

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