Question
If
then
is always
- = 0
- = 1
The correct answer is: ![greater or equal than 1](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABoAAAANCAYAAAC3mX7tAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAMyZLetQAAAGJJREFUeNpjYKAuUAPiWiC+wEBjsBiI04D4PzGK9wOxJYUWEmURyJK9FFr4nxTFlFj4nxzXkWPhf0rCvYgEA8j20X6oryxpFUekWkByqiPXApIs2kuvfESpBegYJ/hBAJMFAMMAKCFOaVyyAAAAWnRFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtbz4mI3gyMjY1OzwvbW8+PG1uPjE8L21uPjwvbWF0aD6bXsh2AAAAAElFTkSuQmCC)
![tan invisible function application open parentheses fraction numerator A over denominator 2 end fraction plus fraction numerator B over denominator 2 end fraction plus fraction numerator C over denominator 2 end fraction close parentheses equals fraction numerator S subscript 1 end subscript minus S subscript 3 end subscript over denominator 1 minus S subscript 2 end subscript end fraction equals tan invisible function application fraction numerator pi over denominator 2 end fraction equals infinity](data:image/png;base64,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)
or
, where
etc.
Now ![left parenthesis x minus y right parenthesis to the power of 2 end exponent plus left parenthesis y minus z right parenthesis to the power of 2 end exponent plus left parenthesis z minus x right parenthesis to the power of 2 end exponent greater or equal than 0](data:image/png;base64,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)
or
. ![left curly bracket because sum x y equals 1 right curly bracket](data:image/png;base64,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)
Related Questions to study
The compound (A) is:
The compound (A) is:
The oxidation number of C in
is:
The oxidation number of C in
is:
has
In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2 ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .
has
In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2 ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .
If
then for all real values of q
If
then for all real values of q
The products (A) , (B) and (C) are:
The products (A) , (B) and (C) are:
In the interval , the equation,
has
In the interval , the equation,
has
oxidised product of , in the above reaction cannot be
oxidised product of , in the above reaction cannot be
Let a, b, c, d R. Then the cubic equation of the type
has either one root real or all three roots are real. But in case of trigonometric equations of the type
can possess several solutions depending upon the domain of x. To solve an equation of the type a
. The equation can be written as
The solution is
where
=
On the domain [–,
] the equation
possess
Let a, b, c, d R. Then the cubic equation of the type
has either one root real or all three roots are real. But in case of trigonometric equations of the type
can possess several solutions depending upon the domain of x. To solve an equation of the type a
. The equation can be written as
The solution is
where
=
On the domain [–,
] the equation
possess
The products (A) and (B) are:
The products (A) and (B) are:
If w is a complex cube root of unity, then the matrix A =
is a-
If w is a complex cube root of unity, then the matrix A =
is a-
Matrix [1 2]
is equal to-
Matrix [1 2]
is equal to-
If A –2B =
and 2A – 3B =
, then matrix B is equal to–
If A –2B =
and 2A – 3B =
, then matrix B is equal to–
The value of x for which the matrix A =
is inverse of B =
is
The value of x for which the matrix A =
is inverse of B =
is
The greatest possible difference between two of the roots if [0, 2
] is
The greatest possible difference between two of the roots if [0, 2
] is