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Maths-

General

Easy

Question

If $A equals open square brackets table row cell cos to the power of 2 end exponent invisible function application theta end cell cell cos invisible function application theta sin invisible function application theta end cell row cell cos invisible function application theta sin invisible function application theta end cell cell sin to the power of 2 end exponent invisible function application theta end cell end table close square brackets$ and $B equals open square brackets table row cell cos to the power of 2 end exponent invisible function application phi end cell cell cos invisible function application phi sin invisible function application phi end cell row cell cos invisible function application phi sin invisible function application phi end cell cell sin to the power of 2 end exponent invisible function application phi end cell end table close square brackets$ are two matrices such that the product AB is the null matrix then $theta minus ϕ$ is equal to

0
multiple of $π$
an odd multiple of $\frac{π}{2}$
None of these.

The correct answer is: an odd multiple of $fraction numerator pi over denominator 2 end fraction$

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