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If A= open square brackets table row cell cos invisible function application theta end cell cell negative sin invisible function application theta end cell row cell sin invisible function application theta end cell cell cos invisible function application theta end cell end table close square brackets, then AAT equals-

  1. open square brackets table row cell cos invisible function application 2 theta end cell cell negative sin invisible function application 2 theta end cell row cell sin invisible function application 2 theta end cell cell cos invisible function application 2 theta end cell end table close square brackets    
  2. open square brackets table row cell cos to the power of 2 end exponent invisible function application theta end cell cell sin to the power of 2 end exponent invisible function application theta end cell row cell sin to the power of 2 end exponent invisible function application theta end cell cell cos to the power of 2 end exponent invisible function application theta end cell end table close square brackets    
  3. open square brackets table row 1 0 row 0 1 end table close square brackets    
  4. open square brackets table row 0 0 row 0 0 end table close square brackets    

The correct answer is: open square brackets table row 1 0 row 0 1 end table close square brackets


    To find  A A to the power of T  of the given matrix.
    We know that, by the property of matrices A A to the power of T  = I

    Therefore, A A to the power of T = open square brackets table row 1 0 row 0 1 end table close square brackets

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