Maths-
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Easy

Question

If f left parenthesis x right parenthesis equals t a n to the power of negative 1 end exponent invisible function application x plus l space l n invisible function application square root of 1 plus x end root minus l n square root of 1 minus x end root. The integral of 1 divided by 2 space f apostrophe left parenthesis x right parenthesis with respect to x to the power of 4 end exponent is -

  1. e to the power of negative x to the power of 4 end exponent end exponent plus c    
  2. negative l n open parentheses 1 minus x to the power of 4 end exponent close parentheses plus c    
  3. e to the power of square root of 1 minus x to the power of 4 end exponent end root end exponent plus c    
  4. l n open parentheses 1 plus x to the power of 4 end exponent close parentheses plus c    

The correct answer is: negative l n open parentheses 1 minus x to the power of 4 end exponent close parentheses plus c


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