Maths-
General
Easy

Question

If P space left parenthesis A union B right parenthesis equals 0.65 comma P space left parenthesis A intersection B right parenthesis equals 0.15, then P space left parenthesis A with ‾ on top right parenthesis plus P space left parenthesis B with ‾ on top right parenthesis equals

  1. 1.2    
  2. 0.2    
  3. 0.8    
  4. 0.6    

hintHint:

P space left parenthesis A with ‾ on top right parenthesis plus P space left parenthesis B with ‾ on top right parenthesis equals space left parenthesis 1 minus space P left parenthesis A right parenthesis space plus space left parenthesis 1 minus P left parenthesis B right parenthesis right parenthesis

The correct answer is: 1.2


     Given : 
    P space left parenthesis A union B right parenthesis equals 0.65 comma P space left parenthesis A intersection B right parenthesis equals 0.15
    By formula :
    P left parenthesis A union B right parenthesis space equals space P left parenthesis A right parenthesis space plus space P left parenthesis B right parenthesis space minus space P left parenthesis A intersection B right parenthesis
P left parenthesis A right parenthesis space plus space P left parenthesis B right parenthesis space equals space P left parenthesis A union B right parenthesis space space plus space P left parenthesis A intersection B right parenthesis
    Substituting the values
    P left parenthesis A right parenthesis space plus space P left parenthesis B right parenthesis space equals space 0.65 space plus space 0.15 space equals space 0.8
    P space left parenthesis A with ‾ on top right parenthesis plus P space left parenthesis B with ‾ on top right parenthesis equals space left parenthesis 1 minus space P left parenthesis A right parenthesis space plus space left parenthesis 1 minus P left parenthesis B right parenthesis right parenthesis
    P space left parenthesis A with ‾ on top right parenthesis plus P space left parenthesis B with ‾ on top right parenthesis equals space 2 minus space 0.8 space equals space 1.2
     

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