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Maths-

General

Easy

Question

If sectors are drawn at the 3 vertices of the triangle which have equal radii then the area of the shaded portion of the given figure is

$\frac{1}{3} π r^{2}$
$\frac{1}{6} π r^{2}$
$\frac{1}{2} π r^{2}$
$\frac{1}{4} π r^{2}$

The correct answer is: $fraction numerator 1 over denominator 2 end fraction pi r to the power of 2 end exponent$

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