Maths-
General
Easy

Question

If the mean of the numbers 27+x, 31+x, 89+x, 107+x,156+x, is 82, then the mean of 130+x, 126+x, 68+x, 50+x, 1+x is

  1. 75    
  2. 157    
  3. 82    
  4. 80    

hintHint:


 

The correct answer is: 75


    To find the mean of the given numbers.
    Given, Mean of numbers 27+x,31+x,89+x,107+x,156+x is 82
    fraction numerator space 27 plus x plus 31 plus x plus 89 plus x plus 107 plus x plus 156 plus x ​ over denominator 5 end fraction = 82 
    410+5x=410 
     
    x=0
     
    Mean of 130+x,126+x,68+x,50+x,1+x is fraction numerator 130 plus x plus 126 plus x plus 68 plus x plus 50 plus x plus 1 plus x over denominator 5 end fraction 
     
    =fraction numerator 375 plus 5 x ​ space over denominator 5 end fraction
     
    =75

    Therefore, the mean of given data is 75.

    Related Questions to study

    General
    Maths-

    The mean of a set of observation is stack x with ̄ on top. If each observation is divided by a, a¹ 0 and then is increased by 10, then the mean of the new set is

    The mean of a set of observation is stack x with ̄ on top. If each observation is divided by a, a¹ 0 and then is increased by 10, then the mean of the new set is

    Maths-General
    General
    maths-

    Compute the median from the following table

    Compute the median from the following table

    maths-General
    General
    maths-

    The following data gives the distribution of height of students

    The median of the distribution is[AMU 1994]</span

    The following data gives the distribution of height of students

    The median of the distribution is[AMU 1994]</span

    maths-General
    parallel
    General
    maths-

    What is the standard deviation of the following series

    What is the standard deviation of the following series

    maths-General
    General
    chemistry-

    Compound (A) The Compound (A) is:

    Compound (A) The Compound (A) is:

    chemistry-General
    General
    maths-

    The order of [x y z] open square brackets table row a h g row h b f row g f c end table close square brackets open square brackets table row x row y row z end table close square brackets is

    The order of [x y z] open square brackets table row a h g row h b f row g f c end table close square brackets open square brackets table row x row y row z end table close square brackets is

    maths-General
    parallel
    General
    maths-

    If the matrix open square brackets table row 1 3 cell alpha plus 2 end cell row 2 4 8 row 3 5 10 end table close square brackets is singular, then alpha =

    If the matrix open square brackets table row 1 3 cell alpha plus 2 end cell row 2 4 8 row 3 5 10 end table close square brackets is singular, then alpha =

    maths-General
    General
    maths-

    If the matrix open square brackets table row 1 3 cell lambda plus 2 end cell row 2 4 8 row 3 5 10 end table close square bracketsis singular, then the value of  is :

    If the matrix open square brackets table row 1 3 cell lambda plus 2 end cell row 2 4 8 row 3 5 10 end table close square bracketsis singular, then the value of  is :

    maths-General
    General
    maths-

    Let A = open square brackets table row cell negative 1 end cell 2 cell negative 3 end cell row cell negative 2 end cell 0 3 row 3 cell negative 3 end cell 1 end table close square bracketsbe a matrix, then(determinant of A ) × (adjoint of inverse of A)is equal to-

    Let A = open square brackets table row cell negative 1 end cell 2 cell negative 3 end cell row cell negative 2 end cell 0 3 row 3 cell negative 3 end cell 1 end table close square bracketsbe a matrix, then(determinant of A ) × (adjoint of inverse of A)is equal to-

    maths-General
    parallel
    General
    maths-

    Let X= open square brackets table row x row y row z end table close square brackets, D = open square brackets table row 3 row 5 row 11 end table close square bracketsand A = open square brackets table row 1 cell negative 1 end cell cell negative 2 end cell row 2 1 1 row 4 cell negative 1 end cell cell negative 2 end cell end table close square brackets. If X = A–1 D, then X is equal to

    Let X= open square brackets table row x row y row z end table close square brackets, D = open square brackets table row 3 row 5 row 11 end table close square bracketsand A = open square brackets table row 1 cell negative 1 end cell cell negative 2 end cell row 2 1 1 row 4 cell negative 1 end cell cell negative 2 end cell end table close square brackets. If X = A–1 D, then X is equal to

    maths-General
    General
    maths-

    If k . open square brackets table row cell negative 1 end cell 2 2 row 2 cell negative 1 end cell 2 row 2 2 cell negative 1 end cell end table close square brackets is an orthogonal matrix, then k is equal to-

    If k . open square brackets table row cell negative 1 end cell 2 2 row 2 cell negative 1 end cell 2 row 2 2 cell negative 1 end cell end table close square brackets is an orthogonal matrix, then k is equal to-

    maths-General
    General
    maths-

    If A is square matrix such that A2 = A, then |A| equals-

    If A is square matrix such that A2 = A, then |A| equals-

    maths-General
    parallel
    General
    maths-

    If the matrix A = open square brackets table row 8 cell negative 6 end cell 2 row cell negative 6 end cell 7 cell negative 4 end cell row 2 cell negative 4 end cell lambda end table close square bracketsis singular, then lambda equal to:

    If the matrix A = open square brackets table row 8 cell negative 6 end cell 2 row cell negative 6 end cell 7 cell negative 4 end cell row 2 cell negative 4 end cell lambda end table close square bracketsis singular, then lambda equal to:

    maths-General
    General
    maths-

    If A2 = 8A + kI where A = open square brackets table row 1 0 row cell negative 1 end cell 7 end table close square brackets then k is :

    If A2 = 8A + kI where A = open square brackets table row 1 0 row cell negative 1 end cell 7 end table close square brackets then k is :

    maths-General
    General
    maths-

    If A = open square brackets table row alpha 0 row 1 1 end table close square brackets and B = open square brackets table row 1 0 row 5 1 end table close square brackets such that A2 = B thealpha is :

    If A = open square brackets table row alpha 0 row 1 1 end table close square brackets and B = open square brackets table row 1 0 row 5 1 end table close square brackets such that A2 = B thealpha is :

    maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.