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Easy

Question

In a capital delta to the power of l e end exponent A B C If T a n invisible function application fraction numerator A over denominator 2 end fraction equals fraction numerator 5 over denominator 6 end fraction comma T a n invisible function application fraction numerator B over denominator 2 end fraction equals fraction numerator 20 over denominator 37 end fraction then T a n invisible function application fraction numerator C over denominator 2 end fraction equals

  1. fraction numerator 5 over denominator 2 end fraction    
  2. fraction numerator 2 over denominator 5 end fraction    
  3. fraction numerator 307 over denominator 122 end fraction    
  4. 7 over 4    

The correct answer is: fraction numerator 2 over denominator 5 end fraction

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