In a plane electromagnetic wave, the electric field oscillates -Turito

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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2 cross times 10 to the power of 10 end exponent$ Hz and amplitude 48 V/m The amplitude of oscillating magnetic field will be

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$\frac{1}{16} \times 10^{- 8} W b / m^{2}$
$16 \times 10^{- 8} W b / m^{2}$
$12 \times 10^{- 7} W b / m^{2}$
$\frac{1}{12} \times 10^{- 7} W b / m^{2}$

Answer:The correct answer is: $16 cross times 10 to the power of negative 8 end exponent W b divided by m to the power of 2 end exponent$

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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $2 cross times 10 to the power of 10 end exponent$ Hz and amplitude 48 V/m The amplitude of oscillating magnetic field will be

$\frac{1}{16} \times 10^{- 8} W b / m^{2}$
$16 \times 10^{- 8} W b / m^{2}$
$12 \times 10^{- 7} W b / m^{2}$
$\frac{1}{12} \times 10^{- 7} W b / m^{2}$

Answer:The correct answer is: $16 cross times 10 to the power of negative 8 end exponent W b divided by m to the power of 2 end exponent$

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In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of Hz and amplitude 48 V/m The amplitude of oscillating magnetic field will be

Answer:The correct answer is:

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