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Maths-

General

Easy

Question

In $triangle A B C comma angle B equals 45 to the power of ring operator end exponent comma angle C equals 55 to the power of ring operator end exponent$ and bisector of $angle$ A meets BC at a point D, then $angle$ ADB and $angle$ ADC are

$60^{\circ}, 80^{\circ}$
$80^{\circ}, 100^{\circ}$
$95^{\circ}, 85^{\circ}$
$85^{\circ}, 95^{0}$

The correct answer is: $95 to the power of ring operator end exponent comma 85 to the power of ring operator end exponent$

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In the given figure, if $P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end text$ and $text end text angle Q R T equals 65 to the power of ring operator end exponent comma$ then the values of x and y respectively are

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In the given figure, if lines PQ and RS intersect at point T, such that $angle P R T equals 40 to the power of ring operator end exponent comma angle R P T equals 95 to the power of ring operator end exponent text end text$ and $text end text angle T S Q equals 75 to the power of ring operator end exponent comma text then end text angle S Q T$

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