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Maths-

General

Easy

Question

In $capital delta$ ABC, D,E,F are the midpoints of sides BC, CA and AB respectively then ar $open parentheses B D E F close parentheses equals$

$\frac{1}{4} a r (△ A B C)$
$\frac{1}{2} a r (△ A B C)$
$\frac{1}{3} a r (△ A B C)$
$a r (△ A B C)$

The correct answer is: $fraction numerator 1 over denominator 2 end fraction a r left parenthesis triangle A B C right parenthesis$

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