Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

In figure, $stack A B with rightwards arrow on top equals 3 stack i with minus on top minus stack j with minus on top comma stack A C with rightwards arrow on top equals 2 stack i with minus on top plus 3 stack j with minus on top$ and $stack D E with rightwards arrow on top equals 4 stack i with minus on top minus 2 stack j with minus on top$ then the area of the shaded region in square units is

5
6
7
8

The correct answer is: 8

$table row cell text end text text W end text text e end text text end text text h end text text a end text text v end text text e end text text end text stack B C with bar on top equals stack B A with rightwards arrow on top plus stack A C with rightwards arrow on top end cell row cell equals left parenthesis negative 3 stack i with minus on top plus stack j with minus on top right parenthesis plus left parenthesis 2 stack i with minus on top plus 3 stack j with minus on top right parenthesis equals negative stack i with minus on top plus 4 stack j with minus on top end cell row cell text end text text V end text text e end text text c end text text t end text text o end text text r end text text end text text a end text text r end text text e end text text a end text text end text text o end text text f end text text end text text t end text text h end text text e end text text end text text s end text text h end text text a end text text d end text text e end text text d end text text end text text r end text text e end text text g end text text i end text text o end text text n end text text end text text i end text text s end text text end text text g end text text i end text text v end text text e end text text n end text text end text text b end text text y end text text end text end cell row cell fraction numerator 1 over denominator 2 end fraction stack E D with rightwards arrow on top cross times stack E B with bar on top plus fraction numerator 1 over denominator 2 end fraction stack E C with rightwards arrow on top cross times stack E D with bar on top end cell row cell equals fraction numerator 1 over denominator 2 end fraction left square bracket stack E D with bar on top cross times left parenthesis stack E B with bar on top minus stack E C with rightwards arrow on top right parenthesis right square bracket end cell row cell equals fraction numerator 1 over denominator 2 end fraction left parenthesis stack E D with bar on top cross times stack C B with bar on top right parenthesis equals fraction numerator 1 over denominator 2 end fraction left parenthesis 16 stack k with minus on top minus 2 stack k with minus on top right parenthesis equals 7 stack k with minus on top end cell row cell text end text text A end text text r end text text e end text text a end text text end text equals ∣ text end text text V end text text e end text text c end text text t end text text o end text text r end text text end text A r a ∣ equals 7 end cell end table$

Related Questions to study

In the figure, $stack D E with bar on top divided by divided by stack B C with bar on top$ and ar $left parenthesis triangle A D E right parenthesis equals a r invisible function application left parenthesis capital delta B E D right parenthesis$ The value of $fraction numerator B D over denominator A B end fraction equals$ ?

In the figure, $stack D E with bar on top divided by divided by stack B C with bar on top$ and ar $left parenthesis triangle A D E right parenthesis equals a r invisible function application left parenthesis capital delta B E D right parenthesis$ The value of $fraction numerator B D over denominator A B end fraction equals$ ?

The median AD of the triangle ABC is bisected at E and BE meets AC at F. If AF:AC =1/k then the value k

The median AD of the triangle ABC is bisected at E and BE meets AC at F. If AF:AC =1/k then the value k

In the figure, $blank stack A B with bar on top divided by stack C D with bar on top divided by stack E F with bar on top$ If AB = 6 cm, BE = 4cm, CD = 10cm, then EF + EC = ... Cm.

In the figure, $blank stack A B with bar on top divided by stack C D with bar on top divided by stack E F with bar on top$ If AB = 6 cm, BE = 4cm, CD = 10cm, then EF + EC = ... Cm.

parallel

In the figure, $angle equals angle A C E D$ , AB = 9cm, AD = 7cm, CD = 8cm and CE = 10cm Then DE = ?

In the figure, $angle equals angle A C E D$ , AB = 9cm, AD = 7cm, CD = 8cm and CE = 10cm Then DE = ?

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top blank$ If AB = 3cm, PB = 2cm and PR = 6cm then QR = ? cm.

In the figure, $stack A B with bar on top divided by divided by stack Q R with bar on top blank$ If AB = 3cm, PB = 2cm and PR = 6cm then QR = ? cm.

In the figure, $stack A B with bar on top divided by divided by stack C D with bar on top$ and $stack A C with rightwards arrow on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC =....units.

Hence AC=12

In the figure, $stack A B with bar on top divided by divided by stack C D with bar on top$ and $stack A C with rightwards arrow on top intersection stack B D with bar on top equals 0 blank$ If OA = 3x – 1, OB = 2x + 1, OC = 5x – 3, OD = 6x – 5 then AC =....units.

Hence AC=12

parallel

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E times$ If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

Hence x=2

Two line segments $stack A B with bar on top$ and $stack C D with bar on top$ intersect at E such that $triangle A C E tilde operator triangle B D E times$ If AE = 4cm, BE = 3cm, CE=6cm and DE = x cm then x = ?

Hence x=2

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle A$ = ?

In the figure, AB = BC = CD = DE = EF and AF = AE Then $angle A$ = ?

In the figure, AB = AC, $angle A equals 48 to the power of ring operator end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

Hence BC=CD

In the figure, AB = AC, $angle A equals 48 to the power of ring operator end exponent$ and $angle A C D equals 18 to the power of ring operator end exponent$ Then

Hence BC=CD

parallel

In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of DABC Then x° + y° =

Hence x+y>180^o

In the figure, ‘x° ’ and ‘y° ’ are two exterior angle measures of DABC Then x° + y° =

Hence x+y>180^o

In $triangle A B C comma text if end text angle A plus angle B equals 84 to the power of ring operator end exponent comma angle B plus angle C equals 146 to the power of ring operator end exponent$ then $angle B equals$

In $triangle A B C comma text if end text angle A plus angle B equals 84 to the power of ring operator end exponent comma angle B plus angle C equals 146 to the power of ring operator end exponent$ then $angle B equals$

The vectors $stack a with minus on top text and end text stack b with minus on top$ are mutually perpendicular then $stack a with minus on top cross times open curly brackets stack a with minus on top cross times open curly brackets stack a with minus on top cross times open parentheses stack a with minus on top cross times stack b with minus on top close parentheses close curly brackets close curly brackets equals$

The vectors $stack a with minus on top text and end text stack b with minus on top$ are mutually perpendicular then $stack a with minus on top cross times open curly brackets stack a with minus on top cross times open curly brackets stack a with minus on top cross times open parentheses stack a with minus on top cross times stack b with minus on top close parentheses close curly brackets close curly brackets equals$

parallel

If $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ be the three vectors such that $stack a with minus on top cross times stack b with minus on top equals stack c with minus on top text and end text stack b with bar on top cross times stack c with bar on top equals stack a with bar on top$ then

If $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ be the three vectors such that $stack a with minus on top cross times stack b with minus on top equals stack c with minus on top text and end text stack b with bar on top cross times stack c with bar on top equals stack a with bar on top$ then

If $stack a with minus on top equals stack i with minus on top plus stack j with minus on top plus stack k with minus on top comma stack b with minus on top equals stack i with minus on top minus stack j with minus on top plus stack k with minus on top$ then $stack i with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack i with minus on top close square brackets plus stack j with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack j with minus on top close square brackets plus stack k with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack k with minus on top close square brackets equals$

If $stack a with minus on top equals stack i with minus on top plus stack j with minus on top plus stack k with minus on top comma stack b with minus on top equals stack i with minus on top minus stack j with minus on top plus stack k with minus on top$ then $stack i with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack i with minus on top close square brackets plus stack j with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack j with minus on top close square brackets plus stack k with minus on top cross times open square brackets open parentheses stack a with minus on top cross times stack b with minus on top close parentheses cross times stack k with minus on top close square brackets equals$

If $a with minus on top to the power of blank comma b with minus on top to the power of blank comma c with rightwards arrow on top$ represents the reciprocal system of vectors of $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ then $Error converting from MathML to accessible text.$

If $a with minus on top to the power of blank comma b with minus on top to the power of blank comma c with rightwards arrow on top$ represents the reciprocal system of vectors of $stack a with minus on top comma stack b with minus on top comma stack c with minus on top$ then $Error converting from MathML to accessible text.$

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.