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General
Easy

Question

In the figure, angle A O B equals 90 to the power of ring operator end exponent, AC = BC, OA = 12 cm and OC = 6.5 cm. Find the area of DA.OB.

  1. 15 c m to the power of 2 end exponent    
  2. 13 c m to the power of 2 end exponent    
  3. 45 c m to the power of 2 end exponent    
  4. 30 c m to the power of 2 end exponent    

The correct answer is: 30 c m to the power of 2 end exponent


    Since mid-point of the hypotenuse of a right triangle is equidistant from the vertices.CA=CB=OC
    CA=CB=6.5 cm
    AB=13 cmIn right triangle OAB, we have

    AB2=OB2+OA2

    132=OB2+122
    OB=5


    ar(AOB)=21(OA×OB)=21(12×15)=30 cm2

    Hence 30 is correct option

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