Maths-
General
Easy

Question

In the following figure, if capital deltaABC is circumscribed over the circle, then x =

  1. 7cm    
  2. 6cm    
  3. 3.9cm    
  4. 10cm    

The correct answer is: 7cm

Related Questions to study

General
maths-

ABC is an Isosceles Triangle inscribed in a Circle such that AB = AC = 17 cm, BC = 16 cm then radius of Circle =

ABC is an Isosceles Triangle inscribed in a Circle such that AB = AC = 17 cm, BC = 16 cm then radius of Circle =

maths-General
General
maths-

In the given fig. if C is the centre of Circle PQC = 25° and PRC =15° then QCR = i

In the given fig. if C is the centre of Circle PQC = 25° and PRC =15° then QCR = i

maths-General
General
maths-

In the following fig. the diameter CD of a Circle is perpendicular to the chord AB. If AB=12 cm and CM = 2 cm. Find radius of Circle.

In the following fig. the diameter CD of a Circle is perpendicular to the chord AB. If AB=12 cm and CM = 2 cm. Find radius of Circle.

maths-General
parallel
General
maths-

ABC is an equilateral triangle of side 6 cm, a Circle with centre ‘O’ passes through the verticles ABC. Find radius of Circle

ABC is an equilateral triangle of side 6 cm, a Circle with centre ‘O’ passes through the verticles ABC. Find radius of Circle

maths-General
General
maths-

From the fig. segments shown are tangents then x =

From the fig. segments shown are tangents then x =

maths-General
General
maths-

In the diagram AB is tangent and ACD is secant, AB = 6 cm and AC = 4 cm, AD=

In the diagram AB is tangent and ACD is secant, AB = 6 cm and AC = 4 cm, AD=

maths-General
parallel
General
maths-

The two Circles below are concentric, the radius of the larger Circle is 10 cm and that of the smaller Circle is 6cm. What is the length of the chord AB ?

The two Circles below are concentric, the radius of the larger Circle is 10 cm and that of the smaller Circle is 6cm. What is the length of the chord AB ?

maths-General
General
maths-

Given O is center of smaller Circle, BD is common chord, ABC, EDO are straight lines. If AED =130°, then C O D =

Given O is center of smaller Circle, BD is common chord, ABC, EDO are straight lines. If AED =130°, then C O D =

maths-General
General
maths-

In the figure x y z=

In the figure x y z=

maths-General
parallel
General
maths-

From the figure left floor P B R equals

From the figure left floor P B R equals

maths-General
General
Maths-

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if stack ∣ O A B with _ below= 35° then left floor E B C equals

In the fig. ‘O’ is the centre of Circle. Chords AC and BD intersect at right angles at E, if stack ∣ O A B with _ below= 35° then left floor E B C equals

Maths-General
General
chemistry-

About 2 to 5% of gypsum left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis is added to Portland cement. It is just to

About 2 to 5% of gypsum left parenthesis C a S O subscript 4.2 H subscript 2 O right parenthesis is added to Portland cement. It is just to

chemistry-General
parallel
General
Maths-

If sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text  then  end text sin squared text end text theta =

If sec to the power of 4 space theta plus sec squared space theta equals 10 plus tan to the power of 4 space theta plus tan squared space theta text  then  end text sin squared text end text theta =

Maths-General
General
biology

Osmosis is the phenomenon expressed by :

Osmosis is the phenomenon expressed by :

biologyGeneral
General
Maths-

If 4 n alpha equals pi comma then the numerical value of tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha is equal to

4 n minus alpha equals pi rightwards double arrow alpha equals fraction numerator pi over denominator 4 n end fraction
n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha
A s comma space left parenthesis 2 n minus 1 right parenthesis alpha equals 2 n alpha minus alpha equals pi over 2 minus alpha
tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan open parentheses pi over 2 minus alpha close parentheses equals c o t space alpha
tan left parenthesis 2 n minus 2 right parenthesis alpha equals tan open parentheses pi over 2 minus 2 alpha close parentheses equals c o t space 2 alpha
S o comma space n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha
equals tan alpha. tan 2 alpha. tan 3 alpha.... c o t space 3 alpha. c o t 2 alpha. c o t alpha
equals left parenthesis tan alpha. c o t alpha right parenthesis left parenthesis tan 2 alpha. c o t alpha right parenthesis left parenthesis tan 3 alpha. c o t 3 alpha right parenthesis......
equals 1.1.1....
equals 1

If 4 n alpha equals pi comma then the numerical value of tan space alpha tan space 2 alpha tan space 3 alpha horizontal ellipsis horizontal ellipsis tan space left parenthesis 2 n minus 1 right parenthesis alpha is equal to

Maths-General
4 n minus alpha equals pi rightwards double arrow alpha equals fraction numerator pi over denominator 4 n end fraction
n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha
A s comma space left parenthesis 2 n minus 1 right parenthesis alpha equals 2 n alpha minus alpha equals pi over 2 minus alpha
tan left parenthesis 2 n minus 1 right parenthesis alpha equals tan open parentheses pi over 2 minus alpha close parentheses equals c o t space alpha
tan left parenthesis 2 n minus 2 right parenthesis alpha equals tan open parentheses pi over 2 minus 2 alpha close parentheses equals c o t space 2 alpha
S o comma space n equals tan alpha. tan 2 alpha. tan 3 alpha....... tan left parenthesis 2 n minus 1 right parenthesis alpha
equals tan alpha. tan 2 alpha. tan 3 alpha.... c o t space 3 alpha. c o t 2 alpha. c o t alpha
equals left parenthesis tan alpha. c o t alpha right parenthesis left parenthesis tan 2 alpha. c o t alpha right parenthesis left parenthesis tan 3 alpha. c o t 3 alpha right parenthesis......
equals 1.1.1....
equals 1
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.