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Maths-

General

Easy

Question

In the given figure, if POQ is a diameter of the circle and PR = QR, then RPQ is

30°
45°
60°
90°

The correct answer is: 45°

$space I n space t r i a n g l e space P R Q space space P R equals P Q space space T h e r e f o r e space angle R P Q equals angle R Q P equals x space left parenthesis a n g l e s space f o r m e d space b y space t h e space e q u a l space s i d e s space o f space a r e space a l s o space e q u a l right parenthesis A l s o angle P R Q equals 90 to the power of ring operator space left parenthesis a n g l e space i n s c r i b e d space i n space a space s e m i space c i r c l e space i s space o f space 90 to the power of ring operator right parenthesis angle P R Q plus angle R P Q plus angle R Q P space equals 180 space left parenthesis a n g l e space s u m space p r o p e r t y space o f space a space t r i a n g l e right parenthesis 90 plus x plus x equals 180 to the power of ring operator 2 x equals 90 to the power of ring operator x equals 45 to the power of ring operator angle R P Q equals 45 to the power of ring operator$

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