Maths-
General
Easy

Question

integral subscript negative pi divided by 4 end subscript superscript pi divided by 4 end superscript   fraction numerator e to the power of x left parenthesis x sin invisible function application x right parenthesis over denominator e to the power of 2 x end exponent minus 1 end fraction d x is equal to

  1. 0    
  2. 2    
  3. e    
  4. none of these    

The correct answers are: 0, e


    Let direction cosines of straight line be l, m, n
    \ 4l + m + n = 0
    l – 2m + n = 0
    Þ fraction numerator l over denominator 3 end fraction equals fraction numerator m over denominator negative 3 end fraction equals fraction numerator n over denominator negative 9 end fraction Þ fraction numerator l over denominator negative 1 end fraction equals fraction numerator m over denominator plus 1 end fraction equals fraction numerator n over denominator 3 end fraction
    \ Equation of straight line is fraction numerator x minus 2 over denominator negative 1 end fraction equals fraction numerator y plus 1 over denominator 1 end fraction equals fraction numerator z plus 1 over denominator 3 end fraction.
    Hence (c) is the correct choice.

    Book A Free Demo

    +91

    Grade*

    Related Questions to study