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Let A = open square brackets table row 1 0 0 row 0 1 1 row 0 cell negative 2 end cell 4 end table close square brackets & I = open square brackets table row 1 0 0 row 0 1 0 row 0 0 1 end table close square brackets and A1 = fraction numerator 1 over denominator 6 end fraction [A2 + cA + dI], find ordered pair (c, d) ?]

  1. (6, 11)    
  2. (–6, –11)    
  3. (–6 , 11)    
  4. (6, –11)    

The correct answer is: (–6 , 11)

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