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Let f left parenthesis x right parenthesis equals x c o s to the power of negative 1 end exponent invisible function application left parenthesis negative s i n invisible function application vertical line x vertical line right parenthesis comma x element of open square brackets negative fraction numerator pi over denominator 2 end fraction comma fraction numerator pi over denominator 2 end fraction close square brackets, then which of the following is true?

Maths-General

  1. f to the power of ' end exponent'/> is increasing in open parentheses negative fraction numerator pi over denominator 2 end fraction comma 0 close parentheses and decreasing in open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses    
  2. f to the power of ' end exponent left parenthesis 0 right parenthesis equals negative fraction numerator pi over denominator 2 end fraction(0)=-π2'/>    
  3. f is not differentiable at x equals 0    
  4. f is decreasing in open parentheses negative fraction numerator pi over denominator 2 end fraction comma 0 close parentheses and increasing in open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses    

    Answer:The correct answer is: f is not differentiable at x equals 0

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