Maths-

General

Easy

Question

# Let L denote the set of all straight lines in a plane. Let a relation R be defined by Then R is-

- Reflexive
- Symmetric
- Transitive
- None of these

Hint:

### A relation R on a set A is said to be symmetric if aRb implies bRa for all a,b∈A.

If R is symmetric, then by the definition of symmetric, if R then R for all m,∈$m,$ \beta $\in L$.

If one line L is given perpendicular to some line m, then m will also be perpendicular to l as well.

## The correct answer is: Symmetric

### To find the type of relation R.

Hence, the relation R is symmetric.

### Related Questions to study

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### Let X={1,2,3,4} and Y={1,3,5,7,9} . Which of the following is relations from X to Y-

So the correct relations are R2 and R3.

### Let X={1,2,3,4} and Y={1,3,5,7,9} . Which of the following is relations from X to Y-

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So the correct relations are R2 and R3.

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Hence, is correct.

### If Q=then-

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Hence, is correct.

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### Let Aand =R-D, then the set D is

Therefore, set of D is .

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Therefore, set of D is .

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### Which set is the subset of all given sets ?

Therefore, { } is a subset of all givens sets.

### Which set is the subset of all given sets ?

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Therefore, { } is a subset of all givens sets.

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### Let A and B be two sets such that n(A) = 70, n(B) = 60 and = 110. Then is equal to-

Therefore, n(A∩B) = 20

### Let A and B be two sets such that n(A) = 70, n(B) = 60 and = 110. Then is equal to-

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Therefore, n(A∩B) = 20

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Therefore, from the given options, is true.

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Therefore, from the given options, is true.

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### The set of intelligent students in a class is-

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### Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A={1, 2, 5}, B = {6, 7} then is-

Therefore, A ⋂ B’ = A.

### Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A={1, 2, 5}, B = {6, 7} then is-

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Therefore, A ⋂ B’ = A.

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Therefore, is equal to = A

### If , then is equal to-

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Therefore, is equal to = A

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