Question

# Let R be a relation defined in the set of real numbers by a R b 1 + ab > 0. Then R is-

- Equivalence relation
- Transitive
- Symmetric
- Anti-symmetric

## The correct answer is: Symmetric

### To find the type of relation R is.

Given relation is $aRb$ is $1+ab>0$,

Considering both a and b are real numbers,

We know that $ab=ba$,
$aRb=1+ab>0=1+ba>0=bRa$,
R is a symmetric relation.

Therefore, the given relation R is symmetric.

### Related Questions to study

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### If , then is equal to-

Therefore, is equal to = A