Maths-

General

Easy

### Question

#### Number of ways to rearrange the letters of the word CHEESE is

- 100
- 115
- 119
- 120

### Hint:

Total number of arrangements of the letters of the word CHEESE = Number of arrangements of 6 things taken all at a time, of which 3 are of one kind

#### The correct answer is: 119

#### The letter CHEESE contains 3 E's

Thus, Total number of arrangements of the letters of the word CHEESE = Number of arrangements of 6 things taken all at a time, of which 3 are of one kind =

## Book A Free Demo

+91

Grade*

Select Grade

### Related Questions to study

Maths-

#### The number of ways in which 17 billiard balls be arranged in a row if 7 of them are black, 6 are red, 4 are white is

Detailed Solution

In the above formula, X = total number of entities,x 1 are the same kind of entities, that is they are identical, x2 are also the same kind of entities but different from x1. Similarly, x3,x4,x5.....xn are the number of identical entities but different from each other.

Before solving the question, we are going to assume that all the balls of the same color are identical. This means that one red ball is identical to another red ball. Similarly, one black ball is identical to all the other black balls and one white ball will be similar to other white balls. Now, we are given that out of 17 balls, 7 of them are black, 6 are red and 4 are white. Now, we will arrange these balls in a row. The formula by which we can arrange the total number of entities which contain similar entities is given as:

In this formula, X is the total number of entities, x1 is the number of identical entities of the first kind,x 2 is the number of identical entities of the second kind, and so on. In our case, X=17,x1=7,x2=6 and x3=4. Thus, we get,

Thus, there are ways in which we can arrange these billiard balls.

In the above formula, X = total number of entities,

Before solving the question, we are going to assume that all the balls of the same color are identical. This means that one red ball is identical to another red ball. Similarly, one black ball is identical to all the other black balls and one white ball will be similar to other white balls. Now, we are given that out of 17 balls, 7 of them are black, 6 are red and 4 are white. Now, we will arrange these balls in a row. The formula by which we can arrange the total number of entities which contain similar entities is given as:

In this formula, X is the total number of entities, x1 is the number of identical entities of the first kind,

Thus, there are ways in which we can arrange these billiard balls.

#### The number of ways in which 17 billiard balls be arranged in a row if 7 of them are black, 6 are red, 4 are white is

Maths-General

Detailed Solution

In the above formula, X = total number of entities,x 1 are the same kind of entities, that is they are identical, x2 are also the same kind of entities but different from x1. Similarly, x3,x4,x5.....xn are the number of identical entities but different from each other.

Before solving the question, we are going to assume that all the balls of the same color are identical. This means that one red ball is identical to another red ball. Similarly, one black ball is identical to all the other black balls and one white ball will be similar to other white balls. Now, we are given that out of 17 balls, 7 of them are black, 6 are red and 4 are white. Now, we will arrange these balls in a row. The formula by which we can arrange the total number of entities which contain similar entities is given as:

In this formula, X is the total number of entities, x1 is the number of identical entities of the first kind,x 2 is the number of identical entities of the second kind, and so on. In our case, X=17,x1=7,x2=6 and x3=4. Thus, we get,

Thus, there are ways in which we can arrange these billiard balls.

In the above formula, X = total number of entities,

Before solving the question, we are going to assume that all the balls of the same color are identical. This means that one red ball is identical to another red ball. Similarly, one black ball is identical to all the other black balls and one white ball will be similar to other white balls. Now, we are given that out of 17 balls, 7 of them are black, 6 are red and 4 are white. Now, we will arrange these balls in a row. The formula by which we can arrange the total number of entities which contain similar entities is given as:

In this formula, X is the total number of entities, x1 is the number of identical entities of the first kind,

Thus, there are ways in which we can arrange these billiard balls.

Maths-

#### Number of permutations that can be made using all the letters of the word MATRIX is

#### Number of permutations that can be made using all the letters of the word MATRIX is

Maths-General

Maths-

#### The number of different signals that can be made by 5 flags from 8 flags of different colours is :

Detailed solution

We have been told that there are 8flags of different colours by taking 5flags at a time. Thus the total number of flags n=8and flags to be taken at a timer = 5

By applying the permutation formula =

Thus, the number of different signals that can be made by 5 flags from 8 flags of different colours is 6720.

We have been told that there are 8flags of different colours by taking 5flags at a time. Thus the total number of flags n=8and flags to be taken at a time

By applying the permutation formula =

Thus, the number of different signals that can be made by 5 flags from 8 flags of different colours is 6720.

#### The number of different signals that can be made by 5 flags from 8 flags of different colours is :

Maths-General

Detailed solution

We have been told that there are 8flags of different colours by taking 5flags at a time. Thus the total number of flags n=8and flags to be taken at a timer = 5

By applying the permutation formula =

Thus, the number of different signals that can be made by 5 flags from 8 flags of different colours is 6720.

We have been told that there are 8flags of different colours by taking 5flags at a time. Thus the total number of flags n=8and flags to be taken at a time

By applying the permutation formula =

Thus, the number of different signals that can be made by 5 flags from 8 flags of different colours is 6720.

Maths-

#### If then A-B=

#### If then A-B=

Maths-General

Maths-

#### , then

#### , then

Maths-General

Maths-

#### If then K=

#### If then K=

Maths-General

Maths-

#### If the remainders of the polynomial when divided by and are 7,3 then the remainder of when devided by is

#### If the remainders of the polynomial when divided by and are 7,3 then the remainder of when devided by is

Maths-General

Maths-

#### If then

#### If then

Maths-General

maths-

#### The partial fractions of are

#### The partial fractions of are

maths-General

Maths-

#### The partial fractions of are

#### The partial fractions of are

Maths-General

Maths-

#### then

#### then

Maths-General

Maths-

#### The partial fractions of are

#### The partial fractions of are

Maths-General

Maths-

#### The partial fractions of are

#### The partial fractions of are

Maths-General

Maths-

#### If then

#### If then

Maths-General

Maths-

#### Let a,b,c such that ,

#### Let a,b,c such that ,

Maths-General