A committee of5 is to be formed from 6 boys and 5 girls the num-Turito

Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

General

Easy

Maths-

A committee of5 is to be formed from 6 boys and 5 girls The number of ways that the committee can be formed so that the committee contains at least one boy and one girl having majority of boys is

Maths-General

240
245
250
275

Answer:The correct answer is: 275

Book A Free Demo

Name*

Mobile*

+91

Email*

Grade*

I agree to get WhatsApp notifications & Marketing updates

Related Questions to study

If n and are integers such that $1 less than straight r less than straight n$ then n c (n‐l, r‐l)=

If n and are integers such that $1 less than straight r less than straight n$ then n c (n‐l, r‐l)=

$22 C subscript 5 plus sum from i equals 1 to 4 of left parenthesis 26 minus i right parenthesis C subscript 4 equals$

$22 C subscript 5 plus sum from i equals 1 to 4 of left parenthesis 26 minus i right parenthesis C subscript 4 equals$

The least value of the natural number $text †† end text$ n satisfying $c left parenthesis n comma 5 right parenthesis plus c left parenthesis n comma 6 right parenthesis greater than c left parenthesis n plus 1 comma 5 right parenthesis$

The least value of the natural number $text †† end text$ n satisfying $c left parenthesis n comma 5 right parenthesis plus c left parenthesis n comma 6 right parenthesis greater than c left parenthesis n plus 1 comma 5 right parenthesis$

$text l. end text straight f to the power of nnn straight C subscript straight r minus 1 end subscript equals 36 comma straight C subscript straight r equals 84 comma straight C subscript straight r plus 1 end subscript equals 126$ then (n, r)=

$text l. end text straight f to the power of nnn straight C subscript straight r minus 1 end subscript equals 36 comma straight C subscript straight r equals 84 comma straight C subscript straight r plus 1 end subscript equals 126$ then (n, r)=

$1 times f to the power of n C subscript 3 colon to the power of 2 n minus 1 end exponent C subscript 2 equals 8 colon 15$ then ‘n’ is

$1 times f to the power of n C subscript 3 colon to the power of 2 n minus 1 end exponent C subscript 2 equals 8 colon 15$ then ‘n’ is

If $alpha$ = mC₂, then $alpha$ C₂ is equal to -

If $alpha$ = mC₂, then $alpha$ C₂ is equal to -

Twelve students compete for a race. The number of ways in which first three places can be taken, is-

Twelve students compete for a race. The number of ways in which first three places can be taken, is-

Given the circuit :

Which of the following is equivalent to the above circuit ?
I)
II)
The true statement in the above is / are

Given the circuit :

Which of the following is equivalent to the above circuit ?
I)
II)
The true statement in the above is / are

The symbolic form of logic of the circuit given below is

The symbolic form of logic of the circuit given below is

The following circuit when expressed in the symbolic form of logic is

The following circuit when expressed in the symbolic form of logic is

For conversion C(graphite)→C(Diamond),the DS is-

For conversion C(graphite)→C(Diamond),the DS is-

chemistry-General

Consider the following processes: DH(kJ/mol) ½A→B +150 3B→2C+D–125 E+A→2D+350 ForB+D→E+2C,DHillbe-

Consider the following processes: DH(kJ/mol) ½A→B +150 3B→2C+D–125 E+A→2D+350 ForB+D→E+2C,DHillbe-

chemistry-General

Enthalpy change for the reaction, 4H_(g) →2H_2(g) is–869.6kJ The dissociation energy of H–H bond is

Enthalpy change for the reaction, 4H_(g) →2H_2(g) is–869.6kJ The dissociation energy of H–H bond is

chemistry-General

ThevaluesofDHandDSforthereaction,C(graphite)+CO(g)→2CO(g)are170kJand170 JK–1respectively.Thisreactionwillbespontaneousat

ThevaluesofDHandDSforthereaction,C(graphite)+CO(g)→2CO(g)are170kJand170 JK–1respectively.Thisreactionwillbespontaneousat

chemistry-General

Assertion: The sum of all4 digited numbers that can be formed using the digits 1,2,4,5,6 without repetition is 479952
Reason: Sum of all $r$ ‐digit numbers formed by taking the given n digits (without zero) is (sum of all the n digits) $cross times left parenthesis n minus left parenthesis A right parenthesis blank P subscript r minus 1 end subscript cross times$ ( $111 horizontal ellipsis. r$ times).

A equals 4 subscript P subscript 3 end subscript end subscript cross times left parenthesis 1 plus 2 plus 4 plus 5 plus 6 right parenthesis cross times 1111 equals 279952

Assertion: The sum of all4 digited numbers that can be formed using the digits 1,2,4,5,6 without repetition is 479952
Reason: Sum of all $r$ ‐digit numbers formed by taking the given n digits (without zero) is (sum of all the n digits) $cross times left parenthesis n minus left parenthesis A right parenthesis blank P subscript r minus 1 end subscript cross times$ ( $111 horizontal ellipsis. r$ times).

A equals 4 subscript P subscript 3 end subscript end subscript cross times left parenthesis 1 plus 2 plus 4 plus 5 plus 6 right parenthesis cross times 1111 equals 279952