General
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Maths-

Statement ‐ I : The equation Error converting from MathML to accessible text. where a is a complex number, represents a circle in Argand plane if lambda is real.
Statement ‐II : The radius of the circle Error converting from MathML to accessible text. is Error converting from MathML to accessible text.

Maths-General

  1. Statement‐l is true, Statement‐2 is true; Statement‐2 is correct explanation for Statement‐ 1.    
  2. Statement‐l is true, Statement‐2 is true; Statement‐2 is not correct explanation for Statement‐l.    
  3. Statement‐l is true, Statement‐2 is false.    
  4. Statement‐l is false, Statement‐2 is true.    

    Answer:The correct answer is: Statement‐l is true, Statement‐2 is false.Result

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    Related Questions to study

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    The third cleavage in frog's development is

    The third cleavage in frog's development is

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    The reason why the right kidney is slightly lower than the left is:

    Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.

    The reason why the right kidney is slightly lower than the left is:

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    Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.
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    This happens if the proximal convoluted tubule is removed from nephron:

    This happens if the proximal convoluted tubule is removed from nephron:

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    physics-

    To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

    V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
    rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃

    To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

    physics-General
    V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
    rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃
    General
    maths-

    The function f left parenthesis x right parenthesis equals sin invisible function application fraction numerator pi x over denominator 2 end fraction plus 2 cos invisible function application fraction numerator pi x over denominator 3 end fraction minus tan invisible function application fraction numerator pi x over denominator 4 end fraction is period with period

    Period of sin invisible function application fraction numerator pi x over denominator 2 end fraction equals fraction numerator 2 pi over denominator pi divided by 2 end fraction equals 4
    Period of cos invisible function application fraction numerator pi x over denominator 3 end fraction equals fraction numerator 2 pi over denominator pi divided by 3 end fraction equals 6
    Period of tan invisible function application fraction numerator pi x over denominator 4 end fraction equals fraction numerator pi over denominator pi divided by 4 end fraction equals 4
    thereforePeriod of f left parenthesis x right parenthesis equals L.C.M. of (4, 6, 4) = 12

    The function f left parenthesis x right parenthesis equals sin invisible function application fraction numerator pi x over denominator 2 end fraction plus 2 cos invisible function application fraction numerator pi x over denominator 3 end fraction minus tan invisible function application fraction numerator pi x over denominator 4 end fraction is period with period

    maths-General
    Period of sin invisible function application fraction numerator pi x over denominator 2 end fraction equals fraction numerator 2 pi over denominator pi divided by 2 end fraction equals 4
    Period of cos invisible function application fraction numerator pi x over denominator 3 end fraction equals fraction numerator 2 pi over denominator pi divided by 3 end fraction equals 6
    Period of tan invisible function application fraction numerator pi x over denominator 4 end fraction equals fraction numerator pi over denominator pi divided by 4 end fraction equals 4
    thereforePeriod of f left parenthesis x right parenthesis equals L.C.M. of (4, 6, 4) = 12
    General
    maths-

    The value of k, for which left parenthesis cos invisible function application x plus sin invisible function application x right parenthesis to the power of 2 end exponent plus k sin invisible function application x cos invisible function application x minus 1 equals 0 is an identity, is

    Given, left parenthesis cos invisible function application x plus sin invisible function application x right parenthesis to the power of 2 end exponent plus k sin invisible function application x cos invisible function application x minus 1 equals 0 comma for all x
    Þ cos to the power of 2 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application x plus 2 cos invisible function application x sin invisible function application x plus k sin invisible function application x cos invisible function application x minus 1 equals 0 comma for all x
    Þ left parenthesis k plus 2 right parenthesis cos invisible function application x sin invisible function application x equals 0 comma for all x Þ k plus 2 equals 0 Þ k equals negative 2

    The value of k, for which left parenthesis cos invisible function application x plus sin invisible function application x right parenthesis to the power of 2 end exponent plus k sin invisible function application x cos invisible function application x minus 1 equals 0 is an identity, is

    maths-General
    Given, left parenthesis cos invisible function application x plus sin invisible function application x right parenthesis to the power of 2 end exponent plus k sin invisible function application x cos invisible function application x minus 1 equals 0 comma for all x
    Þ cos to the power of 2 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application x plus 2 cos invisible function application x sin invisible function application x plus k sin invisible function application x cos invisible function application x minus 1 equals 0 comma for all x
    Þ left parenthesis k plus 2 right parenthesis cos invisible function application x sin invisible function application x equals 0 comma for all x Þ k plus 2 equals 0 Þ k equals negative 2
    General
    maths-

    If A plus B plus C equals 27 0 to the power of o end exponent comma then cos invisible function application 2 A plus cos invisible function application 2 B plus cos invisible function application 2 C plus 4 space sin invisible function application A space sin invisible function application B space sin invisible function application C equals

    A plus B plus C equals 27 0 to the power of o end exponent rightwards double arrow A equals B equals C equals 9 0 to the power of o end exponent comma then
    cos invisible function application 2 A plus cos invisible function application 2 B plus cos invisible function application 2 C plus 4 sin invisible function application A sin invisible function application B sin invisible function application C
    equals cos invisible function application 1 8 0 to the power of o end exponent plus cos invisible function application 1 8 0 to the power of o end exponent plus cos invisible function application 1 8 0 to the power of o end exponent plus 4 sin invisible function application 9 0 to the power of o end exponent sin invisible function application 9 0 to the power of o end exponent sin invisible function application 9 0 to the power of o end exponent
    equals negative 1 minus 1 minus 1 plus 4.1.1.1 equals negative 3 plus 4 equals 1.

    If A plus B plus C equals 27 0 to the power of o end exponent comma then cos invisible function application 2 A plus cos invisible function application 2 B plus cos invisible function application 2 C plus 4 space sin invisible function application A space sin invisible function application B space sin invisible function application C equals

    maths-General
    A plus B plus C equals 27 0 to the power of o end exponent rightwards double arrow A equals B equals C equals 9 0 to the power of o end exponent comma then
    cos invisible function application 2 A plus cos invisible function application 2 B plus cos invisible function application 2 C plus 4 sin invisible function application A sin invisible function application B sin invisible function application C
    equals cos invisible function application 1 8 0 to the power of o end exponent plus cos invisible function application 1 8 0 to the power of o end exponent plus cos invisible function application 1 8 0 to the power of o end exponent plus 4 sin invisible function application 9 0 to the power of o end exponent sin invisible function application 9 0 to the power of o end exponent sin invisible function application 9 0 to the power of o end exponent
    equals negative 1 minus 1 minus 1 plus 4.1.1.1 equals negative 3 plus 4 equals 1.
    General
    Maths-

    Which one of the following is not true

    It is a property of matrix multiplication.

    Which one of the following is not true

    Maths-General
    It is a property of matrix multiplication.
    General
    Maths-

    If A equals open square brackets table row 0 1 row 1 0 end table close square brackets comma B equals open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets then left parenthesis A plus B right parenthesis to the power of 2 end exponentequals

    A B equals open square brackets table row 0 1 row 1 0 end table close square brackets open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets equals open square brackets table row i 0 row 0 cell negative i end cell end table close square brackets
    and B A equals open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets open square brackets table row 0 1 row 1 0 end table close square brackets equals open square brackets table row cell negative i end cell 0 row 0 i end table close square brackets equals negative A B
    therefore A B plus B A equals O
    Hence, left parenthesis A plus B right parenthesis to the power of 2 end exponent equals A to the power of 2 end exponent plus B to the power of 2 end exponent.

    If A equals open square brackets table row 0 1 row 1 0 end table close square brackets comma B equals open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets then left parenthesis A plus B right parenthesis to the power of 2 end exponentequals

    Maths-General
    A B equals open square brackets table row 0 1 row 1 0 end table close square brackets open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets equals open square brackets table row i 0 row 0 cell negative i end cell end table close square brackets
    and B A equals open square brackets table row 0 cell negative i end cell row i 0 end table close square brackets open square brackets table row 0 1 row 1 0 end table close square brackets equals open square brackets table row cell negative i end cell 0 row 0 i end table close square brackets equals negative A B
    therefore A B plus B A equals O
    Hence, left parenthesis A plus B right parenthesis to the power of 2 end exponent equals A to the power of 2 end exponent plus B to the power of 2 end exponent.
    General
    Maths-

    If A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets, then A to the power of 2 end exponent equals

    A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets
    A to the power of 2 end exponent equals A. A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets
    A to the power of 2 end exponent equals open square brackets table row 8 5 row cell negative 5 end cell 3 end table close square brackets.

    If A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets, then A to the power of 2 end exponent equals

    Maths-General
    A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets
    A to the power of 2 end exponent equals A. A equals open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets open square brackets table row 3 1 row cell negative 1 end cell 2 end table close square brackets
    A to the power of 2 end exponent equals open square brackets table row 8 5 row cell negative 5 end cell 3 end table close square brackets.
    General
    Maths-

    The order of left square bracket x y z right square bracket open square brackets table row a g g row f b f row g f c end table close square brackets open square brackets table row cell x end cell row cell y end cell row cell z end cell end table close square brackets is

    Order will be left parenthesis 1 cross times 3 right parenthesis left parenthesis 3 cross times 3 right parenthesis left parenthesis 3 cross times 1 right parenthesis equals left parenthesis 1 cross times 1 right parenthesis.

    The order of left square bracket x y z right square bracket open square brackets table row a g g row f b f row g f c end table close square brackets open square brackets table row cell x end cell row cell y end cell row cell z end cell end table close square brackets is

    Maths-General
    Order will be left parenthesis 1 cross times 3 right parenthesis left parenthesis 3 cross times 3 right parenthesis left parenthesis 3 cross times 1 right parenthesis equals left parenthesis 1 cross times 1 right parenthesis.
    General
    Maths-

    If A equals d i g left parenthesis 2 comma negative 1 , 3 right parenthesis comma B equals d i g left parenthesis negative 1 , 3 comma 2 right parenthesis, then A to the power of 2 end exponent B equals

    A to the power of 2 end exponent B equals left parenthesis A. A right parenthesis B equals open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets. open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets
    equals open square brackets table row 4 0 0 row 0 1 0 row 0 0 9 end table close square brackets open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets equals open square brackets table row cell negative 4 end cell 0 0 row 0 3 0 row 0 0 18 end table close square brackets

    If A equals d i g left parenthesis 2 comma negative 1 , 3 right parenthesis comma B equals d i g left parenthesis negative 1 , 3 comma 2 right parenthesis, then A to the power of 2 end exponent B equals

    Maths-General
    A to the power of 2 end exponent B equals left parenthesis A. A right parenthesis B equals open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets open square brackets table row 2 0 0 row 0 cell negative 1 end cell 0 row 0 0 3 end table close square brackets. open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets
    equals open square brackets table row 4 0 0 row 0 1 0 row 0 0 9 end table close square brackets open square brackets table row cell negative 1 end cell 0 0 row 0 3 0 row 0 0 2 end table close square brackets equals open square brackets table row cell negative 4 end cell 0 0 row 0 3 0 row 0 0 18 end table close square brackets
    General
    Maths-

    Which of the following relations is incorrect

    It is based on fundamental concept

    Which of the following relations is incorrect

    Maths-General
    It is based on fundamental concept
    General
    Maths-

    If A equals open square brackets table row 0 1 row 0 0 end table close square bracketsand A B equals O, then B =

    Since open square brackets table row 0 1 row 0 0 end table close square brackets open square brackets table row cell negative 1 end cell 0 row 0 0 end table close square brackets equals open square brackets table row 0 0 row 0 0 end table close square brackets equals O equals A B
    Þ B equals open square brackets table row cell negative 1 end cell 0 row 0 0 end table close square brackets

    If A equals open square brackets table row 0 1 row 0 0 end table close square bracketsand A B equals O, then B =

    Maths-General
    Since open square brackets table row 0 1 row 0 0 end table close square brackets open square brackets table row cell negative 1 end cell 0 row 0 0 end table close square brackets equals open square brackets table row 0 0 row 0 0 end table close square brackets equals O equals A B
    Þ B equals open square brackets table row cell negative 1 end cell 0 row 0 0 end table close square brackets
    General
    Maths-

    If A equals open square brackets table row cell 1 divided by 3 end cell 2 row 0 cell 2 x minus 3 end cell end table close square brackets comma B equals open square brackets table row 3 6 row 0 cell negative 1 end cell end table close square bracketsand A B equals I, then x =

    vertical line a d j A vertical line
    (As given)
    left right double arrow 3 minus 2 x equals 1 or x equals 1.

    If A equals open square brackets table row cell 1 divided by 3 end cell 2 row 0 cell 2 x minus 3 end cell end table close square brackets comma B equals open square brackets table row 3 6 row 0 cell negative 1 end cell end table close square bracketsand A B equals I, then x =

    Maths-General
    vertical line a d j A vertical line
    (As given)
    left right double arrow 3 minus 2 x equals 1 or x equals 1.