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The angle of projection at which the horizontal range and maximum height of projectile are equal is -

  1. 45 to the power of ring operator end exponent    
  2. theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 0.25 right parenthesis    
  3. theta equals t a n to the power of negative 1 end exponent invisible function application 4 text  or  end text open parentheses theta equals 76 to the power of ring operator end exponent close parentheses    
  4. 60 to the power of ring operator end exponent    

The correct answer is: theta equals t a n to the power of negative 1 end exponent invisible function application 4 text  or  end text open parentheses theta equals 76 to the power of ring operator end exponent close parentheses

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