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Easy

Question

The are of the triangle inscribed in the parabola y2 = 4x, the ordinates of whose vertices are 1, 2 and 4 is

  1. 7/2 sq. unit    
  2. 5/2 sq. unit    
  3. 3/2 sq. unit    
  4. 3/4 sq. unit    

The correct answer is: 3/4 sq. unit


    To find the area of the triangle inscribed inside parabola.
    Given, 1,2,4 are the coordinates and parabola y squared space equals space 4 x.
    for y=1, x = 1 fourth; y=2, x = 1; y=4, x=4.
    so, the vertices are (1 fourth,1) , (1,2), (4,4).
    area of the triangle = 1 half space x space open vertical bar table row cell 1 fourth end cell 1 1 row 1 1 1 row 4 4 1 end table close vertical bar
    = 1/2 (-1/2+3-4)
    =3/4 sq. unit

    Therefore, the area of the triangle is 3/4 sq. unit.

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