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General

Easy

Question

# The are of the triangle inscribed in the parabola y^{2} = 4x, the ordinates of whose vertices are 1, 2 and 4 is

- 7/2 sq. unit
- 5/2 sq. unit
- 3/2 sq. unit
- 3/4 sq. unit

## The correct answer is: 3/4 sq. unit

### To find the area of the triangle inscribed inside parabola.

Given, 1,2,4 are the coordinates and parabola .

for y=1, x = ; y=2, x = 1; y=4, x=4.

so, the vertices are (,1) , (1,2), (4,4).

area of the triangle =

= 1/2 (-1/2+3-4)

=3/4 sq. unit

Therefore, the area of the triangle is 3/4 sq. unit.

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