General
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Maths-

The area bounded by y equals e to the power of x end exponent, Y-axis and the line y=e is

Maths-General

  1. e    
  2. 1    
  3. 2    
  4. fraction numerator e over denominator 2 end fraction    

    Answer:The correct answer is: 1

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    The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

    Displacement = Summation of all the area with sign
    equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

    therefore D i s p l a c e m e n t equals 8 blank m
    Distance = Summation of all the areas without sign
    equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4
    therefore D i s t a n c e equals 16 blank m

    The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 blank s e c are respectively

    physics-General
    Displacement = Summation of all the area with sign
    equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses equals open parentheses 2 cross times 4 close parentheses plus open parentheses negative 2 cross times 2 close parentheses plus open parentheses 2 cross times 2 close parentheses

    therefore D i s p l a c e m e n t equals 8 blank m
    Distance = Summation of all the areas without sign
    equals open vertical bar A subscript 1 end subscript close vertical bar plus open vertical bar negative A subscript 2 end subscript close vertical bar plus open vertical bar A subscript 3 end subscript close vertical bar equals open vertical bar 8 close vertical bar plus open vertical bar negative 4 close vertical bar plus open vertical bar 4 close vertical bar equals 8 plus 4 plus 4
    therefore D i s t a n c e equals 16 blank m
    General
    maths-

    If 32 Tan to the power of 8 theta equals 2 Cos squared space alpha minus 3 cos space alpha text  and  end text 3 cos space 2 theta equals 1 then the general value of 'α ' is

    If 32 Tan to the power of 8 theta equals 2 Cos squared space alpha minus 3 cos space alpha text  and  end text 3 cos space 2 theta equals 1 then the general value of 'α ' is

    maths-General
    General
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    The parabolas y to the power of 2 end exponent equals 4 x comma x to the power of 2 end exponent equals 4 y divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If S subscript 1 end subscript comma S subscript 2 end subscript comma S subscript 3 end subscript are respectively the areas of these parts numbered from top to bottom then S subscript 1 end subscript colon S subscript 2 end subscript colon S subscript 3 end subscript is

    The parabolas y to the power of 2 end exponent equals 4 x comma x to the power of 2 end exponent equals 4 y divide the square region bounded by the lines x=4, y=4 and the co-ordinate axes. If S subscript 1 end subscript comma S subscript 2 end subscript comma S subscript 3 end subscript are respectively the areas of these parts numbered from top to bottom then S subscript 1 end subscript colon S subscript 2 end subscript colon S subscript 3 end subscript is

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    General
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    A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

    Instantaneous velocity is given by the slope of the curve at that instant v equals fraction numerator d s over denominator d t end fraction equals tan invisible function application theta from the figure it is clear that slope of the curve is maximum at point ‘C

    A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

    physics-General
    Instantaneous velocity is given by the slope of the curve at that instant v equals fraction numerator d s over denominator d t end fraction equals tan invisible function application theta from the figure it is clear that slope of the curve is maximum at point ‘C
    General
    physics-

    A particle moves along the sides A B comma B C comma C D of a square of side 25 blank m wuth a velocity of 15 blank m s to the power of negative 1 end exponent. Its average velocity is

    Average velocity =blank fraction numerator T o t a l blank D i s p l a c e m e n t blank over denominator T i m e blank t a k e n blank end fraction equals fraction numerator 25 over denominator 75 divided by 15 end fraction equals 5 m divided by s

    A particle moves along the sides A B comma B C comma C D of a square of side 25 blank m wuth a velocity of 15 blank m s to the power of negative 1 end exponent. Its average velocity is

    physics-General
    Average velocity =blank fraction numerator T o t a l blank D i s p l a c e m e n t blank over denominator T i m e blank t a k e n blank end fraction equals fraction numerator 25 over denominator 75 divided by 15 end fraction equals 5 m divided by s
    General
    physics-

    Velocity-time left parenthesis v-t right parenthesis graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

    Between time interval 20 blank s e c to 40 blank s e c, there is non-zero acceleration and retardation. Hence distance travelled during this interval
    equals Area between time interval 20 blank s e c to 40 blank s e c
    equals fraction numerator 1 over denominator 2 end fraction cross times 20 cross times 3 plus 20 cross times 1 equals 30 plus 20 equals 50 blank m

    Velocity-time left parenthesis v-t right parenthesis graph for a moving object is shown in the figure. Total displacement of the object during the same interval when there is non-zero acceleration and retardation is

    physics-General
    Between time interval 20 blank s e c to 40 blank s e c, there is non-zero acceleration and retardation. Hence distance travelled during this interval
    equals Area between time interval 20 blank s e c to 40 blank s e c
    equals fraction numerator 1 over denominator 2 end fraction cross times 20 cross times 3 plus 20 cross times 1 equals 30 plus 20 equals 50 blank m
    General
    physics-

    The figure shows a double slit experiment P and Q are the slits. The path lengths PX and QX are n lambda and left parenthesis n plus 2 right parenthesis lambda respectively, where n is a whole number and lambda is the wavelength. Taking the central fringe as zero, what is formed at X

    For brightness, path difference equals n lambda equals 2 lambda
    So second is bright.

    The figure shows a double slit experiment P and Q are the slits. The path lengths PX and QX are n lambda and left parenthesis n plus 2 right parenthesis lambda respectively, where n is a whole number and lambda is the wavelength. Taking the central fringe as zero, what is formed at X

    physics-General
    For brightness, path difference equals n lambda equals 2 lambda
    So second is bright.
    General
    maths-

    A) Area bounded by = 2 and coordinate axes
    B) Area bounded by y to the power of 2 end exponent equals 4 x and x to the power of 2 end exponent equals 4 y
    C) Area bounded by y equals 4 x plus x to the power of 2 end exponent between x=0,x=1,x- axis
    D) Area bounded by y to the power of 2 end exponent equals 4 x and y=2x Arrange the above statements in the ascending order of areas.

    A) Area bounded by = 2 and coordinate axes
    B) Area bounded by y to the power of 2 end exponent equals 4 x and x to the power of 2 end exponent equals 4 y
    C) Area bounded by y equals 4 x plus x to the power of 2 end exponent between x=0,x=1,x- axis
    D) Area bounded by y to the power of 2 end exponent equals 4 x and y=2x Arrange the above statements in the ascending order of areas.

    maths-General
    General
    maths-

    If Cos space 20 to the power of ring operator equals k and Cos space x equals 2 bold k squared minus 1, then the possible values of χ between 0 to the power of ring operator and 360 to the power of ring operator  are

    If Cos space 20 to the power of ring operator equals k and Cos space x equals 2 bold k squared minus 1, then the possible values of χ between 0 to the power of ring operator and 360 to the power of ring operator  are

    maths-General
    General
    physics-

    Figure shows the acceleration-time graphs of a particle. Which of the following represents the corresponding velocity-time graphs?

    Since acceleration is constant, therefore there is uniform increase in velocity. So, the v minus t graph is a straight line slopping upward to the right. When acceleration becomes zero, velocity is constant. So v minus t graph is a straight line parallel to the time-axis.

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    physics-General
    Since acceleration is constant, therefore there is uniform increase in velocity. So, the v minus t graph is a straight line slopping upward to the right. When acceleration becomes zero, velocity is constant. So v minus t graph is a straight line parallel to the time-axis.
    General
    maths-

    If gamma Sin space theta equals 3 comma gamma equals 4 left parenthesis 1 plus Sin space theta right parenthesis comma 0 less or equal than theta less or equal than 2 pi then theta = ---

    If gamma Sin space theta equals 3 comma gamma equals 4 left parenthesis 1 plus Sin space theta right parenthesis comma 0 less or equal than theta less or equal than 2 pi then theta = ---

    maths-General
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    physics-

    A particle starts from rest at t equals 0 and undergoes an acceleration a in m s to the power of negative 2 end exponent with time t in seconds which is as shown Which one of the following plot represents velocity V in m s to the power of negative 1 end exponent versus time t in seconds


    Takingthe motion from 0 to 2 blank s
    u equals 0 comma blank a equals 3 m s to the power of negative 2 end exponent comma blank t equals 2 s comma blank v equals ?
    v equals u plus a t equals 0 plus 3 cross times 2 equals 6 m s to the power of negative 1 end exponent
    Taking the motion from 2 blank s to 4 blank s
    v equals 6 plus open parentheses negative 3 close parentheses open parentheses 2 close parentheses equals 0 m s to the power of negative 1 end exponent

    A particle starts from rest at t equals 0 and undergoes an acceleration a in m s to the power of negative 2 end exponent with time t in seconds which is as shown Which one of the following plot represents velocity V in m s to the power of negative 1 end exponent versus time t in seconds

    physics-General

    Takingthe motion from 0 to 2 blank s
    u equals 0 comma blank a equals 3 m s to the power of negative 2 end exponent comma blank t equals 2 s comma blank v equals ?
    v equals u plus a t equals 0 plus 3 cross times 2 equals 6 m s to the power of negative 1 end exponent
    Taking the motion from 2 blank s to 4 blank s
    v equals 6 plus open parentheses negative 3 close parentheses open parentheses 2 close parentheses equals 0 m s to the power of negative 1 end exponent
    General
    physics-

    In Young’s experiment, monochromatic light is used to illuminate the two slits A and B. Interference fringes are observed on a screen placed in front of the slits. Now if a thin glass plate is placed normally in the path of the beam coming from the slit

    In the presence of thin glass plate, the fringe pattern shifts, but no change in fringe width.

    In Young’s experiment, monochromatic light is used to illuminate the two slits A and B. Interference fringes are observed on a screen placed in front of the slits. Now if a thin glass plate is placed normally in the path of the beam coming from the slit

    physics-General
    In the presence of thin glass plate, the fringe pattern shifts, but no change in fringe width.
    General
    physics-

    An engine is moving on a circular track with a constant speed. It is blowing a whistle of frequency 500 blank H z. The frequency received by an observer standing stationary at the centre of the track is

    Since there is no relative motion between the source and listener, so apparent frequency equals original frequency

    An engine is moving on a circular track with a constant speed. It is blowing a whistle of frequency 500 blank H z. The frequency received by an observer standing stationary at the centre of the track is

    physics-General
    Since there is no relative motion between the source and listener, so apparent frequency equals original frequency
    General
    physics-

    A particle starts from rest. Its acceleration open parentheses a close parentheses blank v e r s u s time open parentheses t close parentheses is as shown in the figure. The maximum speed of the particle will be

    Area under acceleration-time graph gives the change in velocity. Hence,
    v subscript m a x end subscript equals fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 11 equals 55 blank m s to the power of negative 1 end exponent
    Therefore, the correct option is [b].

    A particle starts from rest. Its acceleration open parentheses a close parentheses blank v e r s u s time open parentheses t close parentheses is as shown in the figure. The maximum speed of the particle will be

    physics-General
    Area under acceleration-time graph gives the change in velocity. Hence,
    v subscript m a x end subscript equals fraction numerator 1 over denominator 2 end fraction cross times 10 cross times 11 equals 55 blank m s to the power of negative 1 end exponent
    Therefore, the correct option is [b].