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Question

The cartesian equation of r squared c o s space 2 theta equals a squared is

  1. x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent    
  2. x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent    
  3. y to the power of 2 end exponent minus x to the power of 2 end exponent equals a to the power of 2 end exponent    
  4. x to the power of 2 end exponent plus y to the power of 2 end exponent plus a to the power of 2 end exponent equals 0    

hintHint:

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. Here we have to find the cartesian equation of r squared c o s space 2 theta equals a squared.

The correct answer is: x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent


    A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:
    ax² + bx + c = 0
    where a, b, and c are constant terms and x is the unknown variable.
    Now we have given the equation as r squared c o s space 2 theta equals a squared.
    Now we know that:
    cos space 2 theta equals cos squared theta minus sin squared theta.
    So applying this, we get:
    r squared left parenthesis cos squared theta minus sin squared theta right parenthesis equals a squared
    Now lets substitute x=rcosθ and y=rsinθ, we get:
    r squared cos squared theta minus r squared sin squared theta equals a squared
x squared minus y squared equals a squared


     

    Here we used the concept of quadratic equations and solved the problem. We also understood the concept of trigonometric ratios and used the formula to find the equation. So the equation is x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent.

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