Maths-
General
Easy

Question

The centre and radius of the circle r equals c o s space theta minus s i n space theta are respectively

  1. open parentheses fraction numerator 1 over denominator square root of 2 end fraction comma fraction numerator pi over denominator 4 end fraction close parentheses comma fraction numerator 1 over denominator square root of 2 end fraction    
  2. open parentheses fraction numerator 1 over denominator square root of 2 end fraction comma fraction numerator 5 pi over denominator 4 end fraction close parentheses comma fraction numerator 1 over denominator square root of 2 end fraction    
  3. open parentheses fraction numerator 1 over denominator square root of 2 end fraction comma fraction numerator 7 pi over denominator 4 end fraction close parentheses comma fraction numerator 1 over denominator square root of 2 end fraction    
  4. open parentheses fraction numerator 1 over denominator square root of 2 end fraction comma fraction numerator 3 pi over denominator 4 end fraction close parentheses comma fraction numerator 1 over denominator square root of 2 end fraction    

The correct answer is: open parentheses fraction numerator 1 over denominator square root of 2 end fraction comma fraction numerator 7 pi over denominator 4 end fraction close parentheses comma fraction numerator 1 over denominator square root of 2 end fraction

Book A Free Demo

+91

Grade*

Related Questions to study