Maths-
General
Easy

Question

The complete solution set of the equation open vertical bar x to the power of 2 end exponent minus x close vertical bar plus vertical line x plus 3 vertical line equals open vertical bar x to the power of 2 end exponent minus 2 x minus 3 close vertical bar is

  1. left square bracket 1 comma straight infinity right parenthesis
  2. left square bracket negative 3 comma 0 right square bracket union left square bracket 1 comma straight infinity right parenthesis
  3. left parenthesis negative straight infinity comma negative 3 right square bracket
  4. left parenthesis negative straight infinity comma negative 3 right square bracket union left square bracket 0 comma 1 right square bracket

The correct answer is: left parenthesis negative straight infinity comma negative 3 right square bracket union left square bracket 0 comma 1 right square bracket



    table row cell open parentheses x to the power of 2 end exponent minus x close parentheses left parenthesis x plus 3 right parenthesis less or equal than 0 end cell row cell x left parenthesis x minus 1 right parenthesis left parenthesis x plus 3 right parenthesis less or equal than 0 end cell row cell x element of left parenthesis negative infinity comma negative 3 right square bracket union left square bracket 0 , 1 right square bracket end cell end table

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rightwards double arrow negative 2 space sin space x. space cos space 3 x space equals 0
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So comma space straight x element of left square bracket 0 comma space straight pi right parenthesis
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    The equation 4 s i n to the power of 2 end exponent invisible function application x minus 2 left parenthesis square root of 3 plus 1 right parenthesis s i n invisible function application x plus square root of 3 equals 0 has

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