Maths-
General
Easy

Question

The condition for the lines c subscript 1 over r equals a subscript 1 c o s space theta plus b subscript 1 s i n space theta and c subscript 2 over r equals a subscript 2 c o s space theta plus b subscript 2 s i n space theta to be perpendicular is

  1. a subscript 1 end subscript a subscript 2 end subscript plus b subscript 1 end subscript text end text b subscript 2 end subscript equals 0    
  2. a subscript 1 end subscript text end text b subscript 1 end subscript plus a subscript 2 end subscript text end text b subscript 2 end subscript equals 0    
  3. r left parenthesis a c o s space theta plus b s i n space theta right parenthesis equals a b    
  4. r left parenthesis a c o s space theta minus b sin space theta right parenthesis equals a b    

The correct answer is: a subscript 1 end subscript a subscript 2 end subscript plus b subscript 1 end subscript text end text b subscript 2 end subscript equals 0

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