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Question

The equation of common tangent to the parabolas y2 = 4ax and x2 = 4by is

  1. a1/3x + b1/3y + (ab) = 0    
  2. a1/3x + b1/3y + (ab)2/3 = 0    
  3. b1/3x + a1/3y + (ab)1/3 = 0    
  4. b1/3x – a1/3y – (ab)1/3 = 0    

The correct answer is: a1/3x + b1/3y + (ab)2/3 = 0


    Tangent of parabola y2 = 4ax is y = mx + a/m, which also touches to the parabola x2 = 4by rightwards double arrow a/m = – bm2rightwards double arrowm = –(a/b)1/3

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