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Question
The equation of common tangent to the parabolas y2 = 4ax and x2 = 4by is
- a1/3x + b1/3y + (ab) = 0
- a1/3x + b1/3y + (ab)2/3 = 0
- b1/3x + a1/3y + (ab)1/3 = 0
- b1/3x – a1/3y – (ab)1/3 = 0
The correct answer is: a1/3x + b1/3y + (ab)2/3 = 0
Tangent of parabola y2 = 4ax is y = mx + a/m, which also touches to the parabola x2 = 4by a/m = – bm2m = –(a/b)1/3
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