Maths-
General
Easy

Question

The equation of the circle passing through the points (1, 0) and (0,1) and having the smallest radius is:

  1. x to the power of 2 end exponent plus y to the power of 2 end exponent plus x plus y minus 2 equals 0    
  2. x to the power of 2 end exponent plus y to the power of 2 end exponent minus 2 x minus 2 y plus 1 equals 0    
  3. x to the power of 2 end exponent plus y to the power of 2 end exponent minus x minus y equals 0    
  4. x to the power of 2 end exponent plus y to the power of 2 end exponent plus 2 x plus 2 y minus 7 equals 0    

The correct answer is: x to the power of 2 end exponent plus y to the power of 2 end exponent minus x minus y equals 0


    We are given with the circle passing through the points and asked to find the smallest radius
    Circle whose diametric end points are (1, 0) and (0, 1) will be of smallest radius.
    (x−1)(x−0)+(y−0)(y−1)=0
    x^2+y^2−xy=0

    Therefore the correct option is Choice 3

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