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Question

the focus of parabola (y – k)2 = 4 (x – h) always lies between the line x + y = 1 and x + y = 3 then  -

  1. 0 less than h + k less than 2    
  2. 0 less than h + k less than 1    
  3. 1 less than h + k less than 2    
  4. 1 less than h + k less than 3    

The correct answer is: 0 less than h + k less than 2


    To find the correct option.
    Focus of the parabola is (h+1,k)
    It is given that focus lies between x+y=1 and x+y=3
    1<x+y<3
     
    1<h+1+k<3
     
    0<h+k<2

    Therefore, 0<h+k<2 is the correct option.

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