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General
Easy

Question

The least integral value that contained is the range of the function f defined by f left parenthesis x right parenthesis equals fraction numerator x to the power of 2 end exponent plus 1 over denominator log invisible function application open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction is ___

  1. 2    
  2. 3    
  3. 4    
  4. 1    

The correct answer is: 3


    Domain of f is R - {0}
    Given functions f open parentheses x close parentheses equals fraction numerator t over denominator log invisible function application t end fraction comma t greater than 1
    By differentiating, f has minimum at t = e
    text Range of  end text f text  is  end text open square brackets e comma stack stack y with _ below with _ below close parentheses

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