Maths-
General
Easy

Question

The locus of P such that PA2 + PB2 = 10 where A = (2, 0) and B = (4, 0) is

  1. x2 + y2 + 6x + 5 = 0    
  2. x2 – y2 – 6x + 5 = 0    
  3. x2 + y2 – 6x +5 = 0    
  4. None    

hintHint:

In this question, we have to find the locus of P such that P A squared plus P B squared equals 10 where A = (2, 0) and B = (4, 0). A locus is a set of points, in geometry, which satisfies a given condition or situation for a shape or a figure. For we will substitute the value of A and B in the given equation and simplify it to get the required equation.

The correct answer is: x2 + y2 – 6x +5 = 0


    T h e space l o c u s space o f space P space i s comma
space space space space P A squared plus P B squared equals 10
rightwards double arrow left parenthesis left parenthesis x minus 2 right parenthesis squared plus y to the power of 2 end exponent right parenthesis plus left parenthesis left parenthesis x minus 4 right parenthesis squared plus y to the power of 2 end exponent right parenthesis equals 10
rightwards double arrow x squared minus 4 x plus 4 plus y squared plus x squared minus 8 x plus 16 plus y squared equals 10
rightwards double arrow 2 x squared plus 2 y squared minus 12 x plus 10 equals 0
rightwards double arrow x squared plus y squared minus 6 x plus 5 equals 0

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