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General
Easy
Question
The normal of the curve given by the equation x = a (sin
+ cos), y = a (sin – cos) at the point Q is -
- (x + y) cos + (x – y) sin = 0
- (x + y) cos + (x – y) sin = a
- (x + y) cos – (x – y) sin = 0
- (x + y) cos – (x – y) sin = a
+ (x – y) sin = 0
+ (x – y) sin = a
– (x – y) sin = 0
– (x – y) sin = a
The correct answer is: (x + y) cos – (x – y) sin = 0
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