Maths-

General

Easy

Question

# The normal to the curve x = 3 cos – , y = 3 sin – at the point = /4 passes through the point -

- (2, –2)
- (0, 0)
- (–1, 1)
- None of these

Hint:

### Find, Slope of tangent = =

Then find slope of normal, and substitute the values in equation of normal line.

## The correct answer is: (0, 0)

### Given :

x =

At

At P( =

Slope of tangent = =

=

Slope of tangent at point P( =

When slope of tangent at P= -1

Slope of normal at point P = 1

Equation of normal at point P

y - y1 = m(x-x1)

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