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Maths-

General

Easy

Question

The root of the equation [x 1 2] $open square brackets table attributes columnalign left left left columnspacing 1em end attributes row cell 0 1 1 end cell row cell 1 0 1 end cell row cell 1 1 0 end cell end table close square brackets$ $open square brackets table row x row cell negative 1 end cell row 1 end table close square brackets$ = 0 is-

1/3
– 1/3
0
1

The correct answer is: 1/3

To find the root of the equation.
Given, [x 1 2] $open square brackets table attributes columnalign left left left columnspacing 1em end attributes row cell 0 1 1 end cell row cell 1 0 1 end cell row cell 1 1 0 end cell end table close square brackets$ $open square brackets table row x row cell negative 1 end cell row 1 end table close square brackets$ = 0.
$open square brackets table row 3 cell x plus 2 end cell cell x plus 1 end cell end table close square brackets$ x $open square brackets table row x row cell negative 1 end cell row 1 end table close square brackets$ = 0
3x-1 = 0
x = $1 third$

Therefore, root of the equation is $1 third$ .

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