Question

# The value of tan is

## The correct answer is:

### for given expression tan we need to convert sin-1 into tan^{-1}

sin^{-1}(3/5) = tan^{-1}(3/4)^{}

tan[sin-1(3/5)+tan-1(2/3c)] = tan[tan^{-1}(3/4)+tan^{-1}(2/3)]

tan^{-1}(x) + tan^{-1}(y) = tan^{-1}[(x + y) / (1-xy)]

tan[tan-1(3/4)+tan-1(2/3)]=tan[tan^{-1}((3/4+2/3) / (1-3/4*2/3))]

=tan[tan^{-1}(17/6)]

=17/6

ans is 17/6

tan-1(x) + tan-1(y) =tan-1 [(x + y) / (1-xy)] (1 > x y)

tan[tan^{-1}(x)] = x

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