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General
Easy

Question

L t subscript x rightwards arrow 0 end subscript invisible function application fraction numerator e to the power of 7 x end exponent minus 1 over denominator 7 x end fraction

  1. 7    
  2. 1    
  3. 0    
  4. 2    

The correct answer is: 7


    equals 7 cross times L t fraction numerator e to the power of 7 x end exponent minus 1 over denominator 7 x end fraction equals 7 cross times 1 equals 7

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