Question

# Two different packs of 52 cards are shuffled together. The number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination is-

^{52 }C_{26}. 2^{26}
^{104}C_{26}
- 2.
^{52}C_{ 26}
- None of these

^{52 }C_{26}. 2^{26}^{104}C_{26}^{52}C_{ 26}Hint:

### Two different packs of 52 cards are shuffled together. So take all the identical cards together and don't count them repeatedly.

## The correct answer is: ^{52 }C_{26}. 2^{26}

### First of all staple identical cards and select 26 cards = ---(1)

But each of the 26 cards can be selected in 2 ways (belonging to either of the two packs)

These number of ways are = ---(2)

Hence, required number of ways of selection = ×

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