General
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Chemistry-

Methanol and ethanol can be distinguished by the following:

Chemistry-General

  1. By heating with iodine and washing soda
  2. By reaction with caustic soda
  3. By reaction with metallic sodium
  4. By heating with zinc and inorganic mineral acid

    Answer:The correct answer is: By heating with iodine and washing sodaC subscript 2 H subscript 5 O H gives iodoform test.

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    Related Questions to study

    General
    chemistry-

    An alcohol on alk. K M n O subscript 4 oxidation gives first acetone and on further oxidation acetic acid. It is:

    C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H  (Aldehyde and acid of same carbon atoms)
    C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H  (Acid of less carbon atom)

    An alcohol on alk. K M n O subscript 4 oxidation gives first acetone and on further oxidation acetic acid. It is:

    chemistry-General
    C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H  (Aldehyde and acid of same carbon atoms)
    C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H  (Acid of less carbon atom)
    General
    chemistry-

    How many structural isomers are known for C subscript 4 H subscript 10 O ?

    4 alcohols (butan-1-ol; butan-2-ol; 2-methyl butan-1-ol; 2-methyl butan-2-ol) and 3 ethers (diethyl ether, methyl-propyl ether and methyl isopropyl ether).

    How many structural isomers are known for C subscript 4 H subscript 10 O ?

    chemistry-General
    4 alcohols (butan-1-ol; butan-2-ol; 2-methyl butan-1-ol; 2-methyl butan-2-ol) and 3 ethers (diethyl ether, methyl-propyl ether and methyl isopropyl ether).
    General
    chemistry-

    Ethanol is more soluble in water but ether is less soluble because:


    Both shows H-bonding, however the increase in hydrophobic character (due to two alkyl groups in ether), the H-bonding weakens.

    Ethanol is more soluble in water but ether is less soluble because:

    chemistry-General

    Both shows H-bonding, however the increase in hydrophobic character (due to two alkyl groups in ether), the H-bonding weakens.
    General
    chemistry-

    The alcohol that produces turbidity immediately with Z n C I subscript 2 divided by c o n c. space H C I at room temperature

    M i x t u r e space o f space a n space h y d r o u s space Z n C l subscript 2 space end subscript a n d space c o n c. H C l is known as Lucas reagent. Lucas test is used for the distinction between primary, secondary and tertiary alcohols.
    The tertiary alcohol reacts immediately with Lucas reagent producing turbidity. The secondary alcohol gives turbidity within 5-10 min and primary alcohol doesn’t give turbidity at all at room temperature. In the given alternates, 2-hydroxy-2-methyl propane is 3 degree spacealcohol, so it is more reactive.

    The alcohol that produces turbidity immediately with Z n C I subscript 2 divided by c o n c. space H C I at room temperature

    chemistry-General
    M i x t u r e space o f space a n space h y d r o u s space Z n C l subscript 2 space end subscript a n d space c o n c. H C l is known as Lucas reagent. Lucas test is used for the distinction between primary, secondary and tertiary alcohols.
    The tertiary alcohol reacts immediately with Lucas reagent producing turbidity. The secondary alcohol gives turbidity within 5-10 min and primary alcohol doesn’t give turbidity at all at room temperature. In the given alternates, 2-hydroxy-2-methyl propane is 3 degree spacealcohol, so it is more reactive.
    General
    chemistry-

    The acidic character of 1 degree comma 2 degree comma 3 degree spacealcohols, H subscript 2 O and R C identical to C H is of the order

    Alcohols are more acidic than alkynes but less acidic than water thus, the correct order of acidity is H subscript 2 O greater than 1 degree greater than 2 degree greater than 3 degree greater than R C identical to C H

    The acidic character of 1 degree comma 2 degree comma 3 degree spacealcohols, H subscript 2 O and R C identical to C H is of the order

    chemistry-General
    Alcohols are more acidic than alkynes but less acidic than water thus, the correct order of acidity is H subscript 2 O greater than 1 degree greater than 2 degree greater than 3 degree greater than R C identical to C H
    General
    chemistry-

    The conversion of m-nitrophenol to resorcinol involves respectively

    The conversion of m-nitrophenol to resorcinol involves respectively

    chemistry-General
    General
    chemistry-

    At 530 K, glycerol reacts with oxalic acid to produce

    Oxalic acid on reaction with glycerol at 530K temperature furnishallyl alcohol.

    At 530 K, glycerol reacts with oxalic acid to produce

    chemistry-General
    Oxalic acid on reaction with glycerol at 530K temperature furnishallyl alcohol.
    General
    chemistry-

    The following reaction is known as 

    In the presence of anhydrous Z n C l subscript 2 comma phenol form salicyladehyde. It is Gattermann-aldehyde reaction.

    The following reaction is known as 

    chemistry-General
    In the presence of anhydrous Z n C l subscript 2 comma phenol form salicyladehyde. It is Gattermann-aldehyde reaction.
    General
    chemistry-

    On heating glycerol with conc.H subscript 2 S O subscript 4 comma a compound is obtained which has bad odour. The compound is:

    On heating glycerol with conc.H subscript 2 S O subscript 4 comma a compound is obtained which has bad odour. The compound is:

    chemistry-General
    General
    physics-

    A ray of light passes through four transparent media with refractive indices mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text  and end text mu subscript 4 end subscript as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

    For successive refraction through different media mu sin invisible function application theta equalsconstant. Here as theta is same in the two extreme media, mu subscript 1 end subscript equals mu subscript 4 end subscript.

    A ray of light passes through four transparent media with refractive indices mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text  and end text mu subscript 4 end subscript as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

    physics-General
    For successive refraction through different media mu sin invisible function application theta equalsconstant. Here as theta is same in the two extreme media, mu subscript 1 end subscript equals mu subscript 4 end subscript.
    General
    chemistry-

    On conversion into the Grignard reagent followed by treatment with absolute ethanol, how many isomeric alkyl chlorides would yield 2-methylbutane?

    R H space i s space left parenthesis C H subscript 3 right parenthesis subscript 2 space C H bullet C H subscript 2 space C H subscript 3
    Thus, 

    On conversion into the Grignard reagent followed by treatment with absolute ethanol, how many isomeric alkyl chlorides would yield 2-methylbutane?

    chemistry-General
    R H space i s space left parenthesis C H subscript 3 right parenthesis subscript 2 space C H bullet C H subscript 2 space C H subscript 3
    Thus, 
    General
    chemistry-

    What is formed when glycerol reacts with excess of HI?

    When glycerol reacts with HIcomma space i s o minus p r o p y l space iodide is obtained

    What is formed when glycerol reacts with excess of HI?

    chemistry-General
    When glycerol reacts with HIcomma space i s o minus p r o p y l space iodide is obtained
    General
    chemistry-

    General formula for alcohols is:

    General formula for alcohols is C subscript n H subscript left parenthesis 2 n plus 1 right parenthesis O H. Primary alcohols have negative C H subscript 2 space O H space g p. Secondary Alcohols have  and tertiary alcohols have 

    General formula for alcohols is:

    chemistry-General
    General formula for alcohols is C subscript n H subscript left parenthesis 2 n plus 1 right parenthesis O H. Primary alcohols have negative C H subscript 2 space O H space g p. Secondary Alcohols have  and tertiary alcohols have 
    General
    physics-

    A fish is a little away below the surface of a lake. If the critical angle is 49 degree, then the fish could see things above the water surface within an angular range of theta to the power of o end exponent where

    From figure given in question theta equals 2 c equals 98 degree.

    A fish is a little away below the surface of a lake. If the critical angle is 49 degree, then the fish could see things above the water surface within an angular range of theta to the power of o end exponent where

    physics-General
    From figure given in question theta equals 2 c equals 98 degree.
    General
    physics-

    A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be

    D mu subscript R end subscript equals fraction numerator sin invisible function application i over denominator sin invisible function application r to the power of ´ end exponent end fraction rightwards double arrow subscript R end subscript rightwards arrow over short leftwards arrow mu subscript D end subscript equals fraction numerator sin invisible function application r to the power of ´ end exponent over denominator sin invisible function application   i end fraction equals fraction numerator 1 over denominator sin invisible function application C end fraction
    rightwards double arrow sin invisible function application C equals fraction numerator sin invisible function application i over denominator sin invisible function application left parenthesis 90 minus r right parenthesis end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application r end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application i end fraction (as Ði = Ðr)
    rightwards double arrow sin invisible function application C equals tan invisible function application i rightwards double arrow C equals sin to the power of negative 1 end exponent invisible function application left parenthesis tan invisible function application i right parenthesis

    A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be

    physics-General
    D mu subscript R end subscript equals fraction numerator sin invisible function application i over denominator sin invisible function application r to the power of ´ end exponent end fraction rightwards double arrow subscript R end subscript rightwards arrow over short leftwards arrow mu subscript D end subscript equals fraction numerator sin invisible function application r to the power of ´ end exponent over denominator sin invisible function application   i end fraction equals fraction numerator 1 over denominator sin invisible function application C end fraction
    rightwards double arrow sin invisible function application C equals fraction numerator sin invisible function application i over denominator sin invisible function application left parenthesis 90 minus r right parenthesis end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application r end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application i end fraction (as Ði = Ðr)
    rightwards double arrow sin invisible function application C equals tan invisible function application i rightwards double arrow C equals sin to the power of negative 1 end exponent invisible function application left parenthesis tan invisible function application i right parenthesis