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A block of mass m is on an inclined plane of angle null. The block is held stationary by applying a force P parallel to the plane. The direction of force pointing up the plane is taken to be positive. As P is varied from
P subscript 1 end subscript equals m g left parenthesis s i n invisible function application theta minus mu c o s invisible function application theta toblank P subscript 2 end subscript equals m g open parentheses sin invisible function application theta plus mu cos invisible function application theta close parenthesesthe frictional force f versus P graph will look like

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The correct answer is:

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